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egoroff_w [7]
2 years ago
11

A hockey puck is at rest on a flat surface. Then one end of the surface is lifted gradually, forming an inclined plane of increa

sing slope. By measuring the angle of the slope at which the puck begins to slide, what quantity can be calculated?
the coefficient of kinetic friction between the puck and the surface

the mass of the puck

the volume of the puck

the coefficient of static friction between the puck and the surface

Physics
2 answers:
Jlenok [28]2 years ago
6 0

The coefficient of static friction between the puck and the surface.

In fact, that coefficient describes exactly how "hard" it is to cause the puck to start moving, if it starts from an idle condition.

ikadub [295]2 years ago
6 0

Answer:

the coefficient of static friction between the puck and the surface

Explanation:

As per the FBD we can say that as we increase the angle of the inclination the component of force of gravity will counterbalance the friction force

At the condition of just equilibrium when it is just begin to slide then in that case we can say

F_f = mg sin\theta

so here for finding frictional force maximum value we can say

F_f = \mu F_n

here for finding Normal force we can write force balance normal to the inclined plane

F_n = mgcos\theta

now from above equations

\mu (mgcos\theta) = mg sin\theta

\mu = tan\theta

so angle depends on the coefficient of static friction

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An 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching th
ddd [48]

Answer:

1626.4 N

Explanation:

Given that a 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him?

The parameters to be considered are:

Distance S = 3m

Time t = 0.55s

Since the man started from rest, initial velocity u = 0

Using second equation of motion

S = Ut + 1/2at^2

3 = 1/2 × a × 0.55^2

3 = 1/2 × a × 0.3025

a = 3/ 0.15125

a = 19.83 m/s^2

Force = mass × acceleration

Force = 82 × 19.83

Force = 1626.4 N

Therefore, the force that water exerted on him is 1626.4 N

4 0
2 years ago
Need help in this question ???? Hurry please
Digiron [165]

Answer:

how quickly or slowly the object is moving

Hope this helps

7 0
3 years ago
A food packet is dropped from a helicopter during a flood-relief operation from a height of 750 meters. Assuming no drag (air fr
Leviafan [203]

1. Velocity at which the packet reaches the ground: 121.2 m/s

The motion of the packet is a uniformly accelerated motion, with constant acceleration a=g=9.8 m/s^2 directed downward, initial vertical position d=750 m, and initial vertical velocity v_0 = 0. We can use the following SUVAT equation to find the final velocity of the packet after travelling for d=750 m:

v_f^2 -v_i^2 =2ad

substituting, we find

v_f^2 = 2ad\\v_f = \sqrt{2ad}=\sqrt{2(9.8 m/s^2)(750 m)}=121.2 m/s

2. height at which the packet has half this velocity: 562.6 m

We need to find the heigth at which the packet has a velocity of

v_f=\frac{121.2 m/s}{2}=60.6 m/s

In order to do that, we use again the same SUVAT equation substituting v_f with this value, so that we find the new distance d that the packet travelled from the helicopter to reach this velocity:

v_f^2-v_i^2=2ad\\d=\frac{v_f^2}{2a}=\frac{(60.6 m/s)^2}{2(9.8 m/s^2)}=187.4 m

Which means that the heigth of the packet was

h=750 m-187.4 m=562.6 m

3 0
2 years ago
the nucleus and the subatomic particles in the nucleus, what is the charge of the nucleus of an atom?
pychu [463]
The Nucleus contains Protons and Neutrons.

The Neutrons does not have a charge.

The Protons are positively charge.

Hence the charge on the Nucleus, would be the charge of the proton, which is positive.

Hence Nucleus is Positively Charged.
4 0
3 years ago
What will happen to force?
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Answer:

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