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egoroff_w [7]
3 years ago
11

A hockey puck is at rest on a flat surface. Then one end of the surface is lifted gradually, forming an inclined plane of increa

sing slope. By measuring the angle of the slope at which the puck begins to slide, what quantity can be calculated?
the coefficient of kinetic friction between the puck and the surface

the mass of the puck

the volume of the puck

the coefficient of static friction between the puck and the surface

Physics
2 answers:
Jlenok [28]3 years ago
6 0

The coefficient of static friction between the puck and the surface.

In fact, that coefficient describes exactly how "hard" it is to cause the puck to start moving, if it starts from an idle condition.

ikadub [295]3 years ago
6 0

Answer:

the coefficient of static friction between the puck and the surface

Explanation:

As per the FBD we can say that as we increase the angle of the inclination the component of force of gravity will counterbalance the friction force

At the condition of just equilibrium when it is just begin to slide then in that case we can say

F_f = mg sin\theta

so here for finding frictional force maximum value we can say

F_f = \mu F_n

here for finding Normal force we can write force balance normal to the inclined plane

F_n = mgcos\theta

now from above equations

\mu (mgcos\theta) = mg sin\theta

\mu = tan\theta

so angle depends on the coefficient of static friction

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Which of the following mixture can be separate using decantation method?​
vivado [14]

Answer:

Hi sorry for answering here but you didnt put the options there

Explanation:

I'll still try to answer though so maybe the mixture from one of the questions might be something like oil and water which don't mix and can be separated by decantation so something similar would work. Hope this helps

3 0
3 years ago
An engine moves a motorboat through water at a constant velocity of 22 meters/second. If the force exerted by the motor on the b
trapecia [35]

Answer: Option B: 1.3×10⁵ W

Explanation:

Power = \frac{Work \hspace{1mm} done}{Time}

P=\frac{W}{t}

Work Done, W= F.s

Where s is displacement in the direction of force and F is force.

\Rightarrow P = \frac{F.s}{t} =F \times \frac{s}{t}=F.v

where, v is the velocity.

It is given that, F = 5.75 × 10³N

v = 22 m/s

P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W

Thus, the correct option is B

6 0
3 years ago
Which of the following statements describes the movement of air?
Nutka1998 [239]
The movement of air flows from high pressure to low pressure
3 0
3 years ago
A proton moves perpendicular to a uniform magnetic field B with arrow at a speed of 2.50 107 m/s and experiences an acceleration
KIM [24]

Answer:

A) B = 0.009185 T

B) Drection is negative y-direction

Explanation:

A) We are given;

Speed(v) = 2.5 x 10^(7) m/s

Acceleration (a) = 2.2 x 10^(13) m/s²

We also know that charge of proton(q) = 1.6 x 10^(-19)

Mass of proton(m) = 1.67 x 10^(-27)

Now, Since the proton is moving by circular motion, this force is equal to the centripetal force which is given as;

F = qvBsinθ = ma

Since perpendicular, θ = 90°

And so, sinθ = sin 90 = 1

Thus, qvB = ma

Making B the subject gives;

B = ma/qv

B = (1.67 X 10^(-27) X 2.2 X 10^13)) / (1.6 X 10^(-19) X 2.5 X 10^(7))

= 0.009185 T

B) By use of Flemings right hand rule, we can see that the middle finger points toward negative y-direction, so the magnetic field is in the negative y-direction

4 0
3 years ago
Read 2 more answers
If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the
Reika [66]

Answer:

Vapors

Explanation:

We take into account that all the energy from the lightning has been transformed into steam.

\Delta U = Q -  W\\Q = mC \Delta T\\Q = mL

We calculate the amount of energy required by water to convert into steam.

Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J

Q_{change\ to\ steam} = 50 \times 2.256 \times 106 \\= 1.128 \times 10^8 \ J

Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J

From the lightning we received 10^{10} \ J of energy, out of which 1.126 \times 10^8 has been used to convert the water into steam.

Energy left = 10^{10} - 1.126 \times 10^8 = 9.88 \times 10^9 \ J

We use this energy to convert steam into vapors.

Q = \Delta E

Q = \Delta E = mc (T_{f} - T{i})\\T_{f} = \frac {\Delta E}{mc} + T_{i}\\ \\T_{f} = 100 + \frac{9.88 \times 10^{10}}{50 \times 1970}\\T_{f} = 100 + 10^8\\T_{f} = 10 ^{ \ 8} \ {^ \circ } C

With this temperature, we can easily interpret that the vapors will be dissociated in hydrogen and oxygen particles.

5 0
3 years ago
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