Question

Wanda created the poster shown below: A rectangle is shown. The length of the rectangle is labeled as length equal to 32 cm, and the width is labeled as width equal to 36 cm. What would be the dimensions of the poster at fraction 1 over 4 times its current size? Length = 28 cm, width = 32 cm Length = 128 cm, width = 144 cm Length = 8 cm, width = 9 cm Length = 36 cm, width = 40 cm

Answer 1

Divide both dimensions by 4, so 8 by 9

Answer 2

Answer:

Length=8 cm ,width=9 cm .

Step-by-step explanation:

Given in  rectangle

Length of the rectangle=32 cm

Width  of the rectangle= 36 cm

According to question

Length of poster=$\frac{1}{4}$ times  length of rectangle

Length of poster=$\frac{1}{4} \times 32$

Length of poster=8 cm.

By simplification

Width of poster=$\frac{1}{4}$ times width of rectangle

Width of poster=$\frac{1}{4} \times 36$

Width of poster= 9 cm

By simplification

Hence, Length of poster=8 cm and width of poster=9 cm.