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Nata [24]
3 years ago
8

I need help with showing the work

Mathematics
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

Yes. By SAS (side angle side)

Step-by-step explanation:

Ilia_Sergeevich [38]3 years ago
7 0
Dvdddddcxxxdccvfggeveff dc gfvvvvvvvvvvvvv
You might be interested in
What is the mean of -9,-5,-4,-4,-2,0,1,2,3,5
IrinaK [193]

Answer: - 1.3

Step-by-step explanation: I believe that it's -1.3 if you're referring to the arithmetic mean.

(1) Take the sum of -9, -5, -4, -4, -2, 0, 1, 2, 3, 5 and simplify it to -13

(2) Count the number of terms in the data set.

{-9, -5, -4, -4, -2, 0, 1, 2, 3, 5}

{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} - The number of terms in the data set is <u>10.</u>  

(3) Divide the sum by the number of terms and simplify.

-13 / 10 = -1.3 (simplified)

8 0
3 years ago
A Gallup Poll in July 2015 found that 26% of the 675 coffee drinkers in the sample said they were addicted to coffee. Gallup ann
emmasim [6.3K]

Answer:

The 95% confidence interval for the percent of all coffee drinkers who would say they are addicted to coffee is between 21% and 31%.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A confidence interval has two bounds, the lower and the upper

Lower bound:

\pi - M

Upper bound:

\pi + M

In this problem, we have that:

\pi = 0.26, M = 0.05

Lower bound:

\pi - M = 0.26 - 0.05 = 0.21

Upper bound:

\pi + M = 0.26 + 0.05 = 0.31

The 95% confidence interval for the percent of all coffee drinkers who would say they are addicted to coffee is between 21% and 31%.

4 0
3 years ago
Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the d
jolli1 [7]

Answer:

Segment EH and segment E prime H prime both pass through the center of dilation (A)

The complete question related to this found on brainly (ID:16812154) is stated below:

Triangle EFG is dilated by a scale factor of 3 centered at (0, 1) to create triangle E'F'G'. Which statement is true about the dilation?

E(0,5) F(1,1) G(-2,1) H(0,1)

a) segment EH and segment E prime H prime both pass through the center of dilation.

b)The slope of segment EF is the same as the slope of segment E prime H prime.

c) segment E prime G prime will overlap segment EG. segment

d) EH ≅ segment E prime H prime.

Step-by-step explanation:

∆EFG = Original image

∆EFG is dilated to give ∆E'F'G'

∆E'F'G' = New image

Scale factor = 3

Center of dilation = (0,1) = H(0,1)

Coordinates ∆EFG : E(0,5) F(1,1) G(-2,1)

To determine the statement that is true about the dilation from the options,

First we would make a diagram on the coordinates of ∆EFG and center of dilation (H).

Find attached the diagram.

Length GF = 3unit

Length G'F' = 3×scale factor = 9unit

Length EH = 4unit

Length E'H' = 4×scale factor = 12unit

Then we would move 3units to the left on same line from G to get the coordinate of G'(mark the point).

Also move 3units to the right on same line from F to get the coordinate of F'(mark the point).

Both of these give length of G'F' = 9unit

Now move 8units to the top from E to get the coordinate of E'(mark the point).

From this you get length E'H' = 12unit

Draw lines connecting the three points to get ∆E'F'G'

See diagram for better understanding

From the diagram, EH and E'H' both pass through (0,1). The other options are wrong.

Therefore, Segment EH and segment E prime H prime both pass through the center of dilation (A)

5 0
3 years ago
Help (Picture attached)
Jlenok [28]
I think that its 36...

6 0
3 years ago
Read 2 more answers
Determine the simple interest when: principal: $205,435 interest rate: 2.8%, time: 15 year
Vesna [10]
<h2>$86282.7</h2>

<em>Step-by-step explanation:</em>

<h3><em>p</em><em>r</em><em>i</em><em>n</em><em>c</em><em>i</em><em>p</em><em>l</em><em>e</em><em> </em><em>(</em><em>p</em><em>)</em><em> </em><em>=</em><em> </em><em>$</em><em>2</em><em>0</em><em>5</em><em>,</em><em>4</em><em>3</em><em>5</em></h3><h3><em>r</em><em>a</em><em>t</em><em>e</em><em> </em><em>(</em><em>r</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>8</em><em>%</em></h3><h3><em>t</em><em>i</em><em>m</em><em>e</em><em> </em><em>(</em><em>t</em><em>)</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em><em> </em><em>y</em><em>e</em><em>a</em><em>r</em><em>s</em></h3><h3><em>s</em><em>i</em><em>m</em><em>p</em><em>l</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>e</em><em>s</em><em>t</em><em> </em><em>=</em><em> </em><em>(</em><em>p</em><em> </em><em>×</em><em> </em><em>r</em><em> </em><em>×</em><em> </em><em>t</em><em>)</em><em> </em><em>÷</em><em> </em><em>1</em><em>0</em><em>0</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>(</em><em>2</em><em>0</em><em>5</em><em>,</em><em>4</em><em>3</em><em>5</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>8</em><em> </em><em>×</em><em> </em><em>1</em><em>5</em><em>)</em><em> </em><em>÷</em><em> </em><em>1</em><em>0</em><em>0</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>8,628,270</em><em> </em><em>÷</em><em> </em><em>1</em><em>0</em><em>0</em></h3><h3><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>8</em><em>6</em><em>2</em><em>8</em><em>2</em><em>.</em><em>7</em></h3>

<h2>MARK ME AS BRAINLIST</h2><h2>PLZ FOLLOW ME</h2>
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