Write the equation in slope- intercept form of the line that has a slope of -3 and contains the point (1,1)
1 answer:
Slope-intercept form is y = mx + b, where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept.
Since we know the slope, plug it into the base equation:
y = mx + b
y = -3x + b
We don't know what <em>b</em> is, so plug the point we have into the equation:
y = -3x + b
1 = -3(1) + b
1 = -3 + b
b = 4
Now that we know <em>b</em>, input it into the partial equation:
y = -3x + b
y = -3x + 4 is the equation of the line.
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2p+1.5=total spent I hope this helps
Answer:
A (10, -9)
B (0,-9)
C (0,-1)
D (10,-1)
Step-by-step explanation:
Negate the x-coordinates of each of the vertices
9.21 - (-5.51)
9.21 + 5.51 = 14.72
The distance is 14.72
-3(x-14)+9x=6x+24
-3x+42+9x=6x+24
-3x+9x-6x=-24-42
0=-18