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Viefleur [7K]
4 years ago
13

As you explore career options why is it important to take personal inventory is and assessments

Computers and Technology
2 answers:
Maksim231197 [3]4 years ago
6 0
To make yourself happy! There's no point in pursuing a career if it doesn't bring you happiness and satisfaction in the end. To also helps a lot in terms of money, as you won't waste your time paying for items/classes related to the career to just find out you'd rather do another career.
solniwko [45]4 years ago
6 0

They help you learn what type of career might be best for you.

You might be interested in
Create a security management policy that addresses the management and the separation of duties throughout the seven domains of a
klio [65]

Seven Domains of IT Infrastructure Seven domains can be found in a typical IT infrastructure. They are as follows: User Domain, Workstation Domain, LAN Domain, LAN-to-WAN Domain, Remote Access Domain, WAN Domain, and System/Application Domain.

Explanation:

User Domain : The User Domain covers all theusers (of any rank) that haveaccess to the other six domains.

RISKS:

  • User can destroy data in application(intentionally or not) and delete all
  • User can insert infected CD or USBflash drive into the work computer

Workstation Domain : A computer of an individual user where the production takes place

RISKS:

  • The workstation’s OS can have a known software vulnerability thatallows a hacker to connect remotelyand steal data.
  • A workstation’s hard drive can fail causing lost data

LAN Domain : Contains all of the workstations,hubs, switches, and routers. TheLAN is a trusted zone

RISKS:

  • A worm can spread through the LANand infect all computers in it.
  • LAN server OS can have a knownsoftware vulnerability.

WAN Domain : Stands for Wide Area Network and consists of the Internet and semi-private lines

RISKS:

  • Service provider can have a major network outage.
  • Server can receive a DOS or DDOS attack.
  • A FTP server can allow anonymously uploaded illegal software

LAN / WAN Domain : The boundary between the trusted and un-trusted zones.The zones are filtered with a firewall

RISKS:

  • Weak ingress/egress traffic filteringcan degrade performance.
  • A firewall with unnecessary portsopen can allow access from the Internet

System / Application Storage Domain : This domain is made up of user-accessed servers suchas email and database

RISKS:

  • A fire can destroy primary data
  • A DOS attack can cripple the organization’s email

Remote Access Domain  :The domain in which a mobileuser can access the local network remotely, usually through a VPN

RISKS:

  • Communication circuit outage candeny connection.
  • Remote communication from officecan be unsecured.
  • VPN tunneling between remotecomputer and ingress/egress routercan be hacked
6 0
3 years ago
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
4 years ago
01110111 01101000 01100001 01110100 00100000 01101001 01110011 00100000 00110001 00101011 00110001
Lera25 [3.4K]
Same lol thesis so me right now
7 0
4 years ago
What process combines data from a list with the content of a document to provide personalized documentsWhat
Morgarella [4.7K]
Mail merge can combine data with the content of a document to make personalized documents.
6 0
3 years ago
Read 2 more answers
2. The factorial of a positive integer n is the product of the integers from 1 to n. You can express the factorial of a positive
Molodets [167]

Answer:

import java.io.*;

import java.util.Scanner;//importing the scanner.

class Factorial {

public static void main (String[] args) {

    Scanner fact=new Scanner(System.in);//creating a scanner object for taking the input.

    int t,n;//t for number of times the user want to calculate the factorial and n for factorial.

    System.out.println("How many times you want to calculate the factorial");

    t=fact.nextInt();//taking input of t.

    while(t>0)

    {

        int f=1;//f for calculating the variable.

        n=fact.nextInt();//taking input of n .

        if(n>10||n<1)//if n is out of range then again taking input.

        {

           while(n>10 || n<1)

                {

                        System.out.println("Please Enter the Valid Input");

                 n=fact.nextInt();

                }

               for(int i=1;i<=n;i++)//calculating the factorial.

               {

                   f*=i;

               }

               System.out.println("The factorial is: "+ f);

        }

        else // if n is in  range then definitely calculating the factorial.

        {

             for(int i=1;i<=n;i++)// calculating the factorial.

               {

                   f*=i;

               }

               System.out.println("The factorial is: "+ f);

        }

    }

}

}

Output:-

How many times you want to calculate the factorial

2

-5

Please Enter the Valid Input

4

The factorial is: 24

5

The factorial is: 120

Explanation:

The above written code is for calculating the factorial of an integer the number of times user want to calculate the factorial.The code wants user to enter again until the value entered by the user is in range.If the value is in range then it definitely calculates the factorial.

6 0
3 years ago
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