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Reptile [31]
3 years ago
12

What happens when your computer is in Hibernate mode?

Computers and Technology
1 answer:
marusya05 [52]3 years ago
8 0
It keeps you logged in to everything but it turns the screen off to save power.
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Which of the following scenarios falls into the category of network crimes?
solong [7]

Answer:

B

Explanation:

Hope it helps!

3 0
2 years ago
Read 2 more answers
An algorithm whose worst-case time complexity is bounded above by a polynomial function of its size is called a(n)
Sedaia [141]

Answer:

polynomial-bounded algorithms

Explanation:

There are two algorithm complexities and they are time and space complexities. They can be denoted with the big-O notation. The big-o notation for a time and space complexity gets the worst-case time and space respectively.

The time complexity gets the measure of the execution time of an algorithm. When the time function is a polynomial ( k^n + k^n-1 ...) then the algorithm is said to be a polynomial-bounded algorithm.

4 0
2 years ago
A file ____ shows the location of a file or folder
UkoKoshka [18]

Answer:

Path

Explanation:

correct answer: Path

(Hope this helps can I pls have brainlist (crown)☺️)

6 0
2 years ago
Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a
Ksenya-84 [330]

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

7 0
3 years ago
Bytes are arrangements of
tigry1 [53]
The answer is B. Eight bits
7 0
3 years ago
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