If $5000 is invested at 7.8% interest compounded monthly, how much would you have after 54 months?

Hi, how do we do this question?

Nutka1998 [239]

Answer:

$\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{-2(ln|3x + 1| - 3x)}{9} + C$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Factoring

Algebra II

Polynomial Long Division

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals
Integration Constant C
Indefinite Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Logarithmic Integration

U-Substitution

Step-by-step explanation:

*Note:

You could use u-solve instead of rewriting the integrand to integrate this integral.

Step 1: Define

Identify

$\displaystyle \int {\frac{2x}{3x + 1}} \, dx$

Step 2: Integrate Pt. 1

[Integrand] Rewrite [Polynomial Long Division (See Attachment)]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \int {\bigg( \frac{2}{3} - \frac{2}{3(3x + 1)} \bigg)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \int {\frac{2}{3}} \, dx - \int {\frac{2}{3(3x + 1)}} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}\int {} \, dx - \frac{2}{3}\int {\frac{1}{3x + 1}} \, dx$
[1st Integral] Reverse Power Rule: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{3}\int {\frac{1}{3x + 1}} \, dx$

Step 3: Integrate Pt. 2

Identify variables for u-substitution.

Set u: $\displaystyle u = 3x + 1$
[u] Differentiate [Basic Power Rule]: $\displaystyle du = 3 \ dx$

Step 4: Integrate Pt. 3

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}\int {\frac{3}{3x + 1}} \, dx$
[Integral] U-Substitution: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}\int {\frac{1}{u}} \, du$
[Integral] Logarithmic Integration: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}ln|u| + C$
Back-Substitute: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{2}{3}x - \frac{2}{9}ln|3x + 1| + C$
Factor: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = -2 \bigg( \frac{1}{9}ln|3x + 1| - \frac{x}{3} \bigg) + C$
Rewrite: $\displaystyle \int {\frac{2x}{3x + 1}} \, dx = \frac{-2(ln|3x + 1| - 3x)}{9} + C$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

8 0

3 years ago

Please help i have an exam next week and im really stuck on this

ruslelena [56]

Answer:

Area = 96 square cm

Step-by-step explanation:

Area of the figure = (2 x Area of triangles) + Area of square

$Area \ of \ triangle = \frac{1}{2} \times base \ height = \frac{1}{2} \times 8\times 4 = 16cm^2\\\\Area \ of \ square = side \times side = 8 \times 8 = 64cm^2$

Therefore, $Area \ of \ the\ figure = (2 \times 16) + 64 = 32 + 64 = 96cm^2$

6 0

3 years ago

Read 2 more answers

If ab = 10 and a2 + b2 = 30, what is the value of (a + b)^2?

Bogdan [553]

Ab=10
a^2+b^2=30
((a+b)^2=a^2+2ab+b^2=a^2+b^2+2*10=30+20=50

6 0

3 years ago

Read 2 more answers

Look at the figure. Which construction is illustrated? 7. Which is the equation of the line with slope 3 that contains point (−1

kenny6666 [7]

Answer:

Option B

Step-by-step explanation:

I can't do the 'figure question' because it lacks info, but I can answer the point-slope question.

Point-slope form is: $y-y_1=m(x-x_1)$

'm' - slope

'(x1, y1)' - point

We are given the slope of 3 and the point (-1, 5).

Replace 'x1', 'y1', and 'm' with the appropriate values.

$y-y_1=m(x-x_1)\rightarrow \boxed{y-5=3(x+1)}$

Option B should be the correct answer.

7 0

3 years ago

Pete went to the store. He bought 3 pounds of chili peppers, 5 pounds of habanero peppers,

tangare [24]

Chili peppers: 3 pounds x $2 per lb = $6
Habanero peppers: 5 pounds x $2 per lb = $10
Red bell peppers: 1 pound x $2 = $2
6+10+2= $18 dollars spent total

6 0

2 years ago