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3 years ago

Need help asap!

Mathematics

2 answers:

Maslowich3 years ago

8 0

TU=AB since they are congruent figure. So AB=13

devlian [24]3 years ago

8 0

Answer: $\overline{AB}=13\ units$

Step-by-step explanation:

Given: Figure TUVW ≅ figure ABCD

UV=9 , WT=17 , and TU=13

We know that if two figures are congruent then their corresponding parts (angles and sides) are also equal.

Therefore, if Figure TUVW ≅ figure ABCD then

$\overline{AB}=\overline{TU}=13\ units\\\overline{BC}=\overline{UV}=9\ units\\\overline{CD}=\overline{VW}\\\overline{AD}=\overline{TW}=17\ units$

Hence, the measure of $\overline{AB}=13\ units$

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A bag has four green marbles, three red marbles, and three yellow marbles. What is the probability that you pick a green marble,

Kipish [7]

So you have 10 marbles all together. you remove one and dont replace it. it will be 3/9 which simplifies to 1/3.

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3 years ago

I need with this. Someone help please.

seraphim [82]

Answer:

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Step-by-step explanation:

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<em>Hope this helps!!</em>

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3 years ago

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saw5 [17]

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3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Pls help and explain it how i do i this <3

jolli1 [7]

Answer:

You input the equation they give you into the table to get an outcome. The Equation they gave you is x=y. simply, what ever X is, thats what y is. x=y. On the table it says that X is 3. If x is 3 then y is three because they are equal. if X is 7 then Y is 7. its the same throughout the whole table. To write it as an ordered pair you write (X,Y) if x is three y is three so the ordered pair would look like (3,3)

4 0

3 years ago