The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
Learn more about extraneous solution on:
brainly.com/question/295656
#SPJ4
Answer:
the answer to the problem is 4,15,8,3
Answer:
6/9, 12/18 (just 6 then 12)
Step-by-step explanation:
Please mark brainlest
Answer:
-1 is the inverse of 16 modulo 17.
Step-by-step explanation:
To find : An inverse of 16 modulo 17 i.e.
?
Solution :
First we find the GCD of (17,16) using Euclid's algorithm,

Remainder is 1.
Which means, GCD(17,16)=1
Using back substitution we get,



i.e. -1 is the inverse of 16 modulo 17.
On comparing with 
The value of x=-1.