3 years ago

Given g(x) = 2x + 1, solve for a when g(x) = 7.

Mathematics

1 answer:

Over [174]3 years ago

7 0

You would evaluate by plugging in the given number of 7 to get your answer.

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what is the approximate percent increase when the population of a town increases from 12089 to 15025? round the amounts to the n

bulgar [2K]

The rate of increase is
$\frac{15025}{12089}\approx1.242865$

The percent of increase is then
$(1.242865-1)*100\%=0.242865*100\%=24.2865\%$

6 0

3 years ago

Read 2 more answers

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Ipatiy [6.2K]

Answer:

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

Step-by-step explanation:

$2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c = - 3 \\\\x = \frac{-b^2\ \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\$