<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
X=y-2
2y=5x-17
Substituting for x into the second equation, we find
2y=5(y-2)-17
2y=5y-10-17
-3y=-27
y=9
So x=7
Thus, the two numbers are 7 and 9.
Answer:
option C is correct answer ..
Step-by-step explanation:
angle A + angle B + angle C = 180° ( by angle sum property of triangle )
3x + 4x-19+ 3x -1 = 180
10x + -20 = 180
10x = 180 +20 = 200
x = 200/10 = 20 °
angle A = 3× 20 = 60 °
angle B = 4× 20 - 1 9 = 61 °
angle C = 3× 20 -1 = 59 °
angle B is greatest so side opposite to it will be greatest in length ....so length of AC is greatest ....
so option C is the correct answer of this question ...
plz mark my answer as brainlist plzzzz vote me also as I have done this question by taking a lot of time Hope it will be helpful for you ....
