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Yuri [45]
4 years ago
9

HELP ME ASAP THANK YOU

Mathematics
2 answers:
OverLord2011 [107]4 years ago
6 0
To solve for the output value of 1 you will substitute 1 for x.

y = 3(1) + 1
y = 3+1
y = 4

So the output value for the input value of 1 is 4.
Mila [183]4 years ago
3 0
The answer is C. 4.

Y=3(1)+1
Y=3+1
Y=4
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HELP PLEASE!!!!
Stels [109]

-9 is the answer

your welcome

5 0
3 years ago
Kareem ran three times last week. Here are the distances he rall
EleoNora [17]

Simply add the three decimals to find Kareem's total distance.

1.6 + 11.5 + 15 = 28.1

(0.6 + 0.5 = 1.1, 1 + 11 + 15 = 27, 27 + 1.1 = 28.1)

<h2>Answer:</h2>

<u>Kareem ran </u><u>28.1 km</u><u> on those three days.</u>

I hope this helps :)

8 0
3 years ago
Nate borrowed $62,000 at 9.4% interest per year if he owed a total of $910.90 in when he repaid the loan how many days do they k
OverLord2011 [107]
The formula for simple annual interest is:

I = Prt

where,

I = Interest accumulated = $910.90
P = Principal Amount = $62000
r = Interest rate = 9.4% = 0.094
t = time in years

Using the values in above equation, we get:

910.90 = 62000 x 0.094 x t

⇒ t = 910.90/(62000 x 0.094) = 0.156

This is the time in years. Since there are 365 days in a year, the time in days will be:

t = 0.156 x 365 = 57 (rounded to nearest day)

This means, Nate kept the borrowed money for 57 days
6 0
3 years ago
Let f(x)=x^3 and g(x)= √x, and h(x)=x/3. Find each of the following: f(g(h(6)))
rewona [7]

Answer:

go from inside out.

h(x)=x/3

(\sqrt{2})^{3}=> h(6) = 6/3 = 2

g(x) = \sqrt{x}

=> g(h(6)) = g(2) = \sqrt{2}

f(x) = x^{3}

=> f(g(h(6))) = f(\sqrt{2} ) = (\sqrt{2} )^{3}

6 0
3 years ago
You pull out the plug from the bathtub. After 30 seconds, there are 13 gallons of water left in the tub. One minute after you pu
kari74 [83]
There were 15 gallons of water to begin with. hope this helps
6 0
3 years ago
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