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Yuri [45]
4 years ago
9

HELP ME ASAP THANK YOU

Mathematics
2 answers:
OverLord2011 [107]4 years ago
6 0
To solve for the output value of 1 you will substitute 1 for x.

y = 3(1) + 1
y = 3+1
y = 4

So the output value for the input value of 1 is 4.
Mila [183]4 years ago
3 0
The answer is C. 4.

Y=3(1)+1
Y=3+1
Y=4
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What is the answer to the question A 0.10
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Yeah it’s A q0 good luck
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3 years ago
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Quadrilaterals ABCD and EFGH are similar. If the perimeter of the quadrilateral ABCD is equal to 4y² what is the perimeter of th
UNO [17]

Answer:

Can't be determined.

Step-by-step explanation:

From the fact that the quadrilaterals are similar:

Corresponding sides are in proportion and

Corresponding angles are congruent.

We can't create a proportion, so there's nothing else that we can determine.

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3 years ago
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-4x &lt; 28<br>does anyone know the solution and answer?​
ratelena [41]

Answer:

x>−7

Explanation:

Let's solve your inequality step-by-step.

−4x<28

Step 1: Divide both sides by -4.

−4x/−4 < 28/−4

x>−7

Answer: x>−7

6 0
2 years ago
Please help . In the figure, ∆BAT ≅ ∆CAT. Which statement is not true by CPCTC?
masya89 [10]

Answer:

  \overline{CS}\cong\overline{ST}

Step-by-step explanation:

The congruence statement for the triangles does not list point (or angle) S, so no claim about segments or angles involving S will be supported by the congruence statement.

The statement

  \Delta BAT\cong\Delta CAT tells you ...

     \angle TBA\cong\angle TCA\\\angle BAT\cong\angle CAT\\\angle ATB\cong\angle ATC\\\overline{BA}\cong\overline{CA}\\\overline{AT}\cong\overline{AT}\\\overline{TB}\cong\overline{TC}

No other claims can be made using CPCTC. The statement among the answer choices that is not true by CPCTC is ...

  \boxed{\overline{CS}\cong\overline{ST}}

3 0
3 years ago
2. Find the first, fourth, and tenth terms of the arithmetic
sladkih [1.3K]

Answer:

<u>The correct answer is B. -6, -5 2/5, - 4 1/5</u>

Step-by-step explanation:

Let's find the 1st, 4th and 10th terms of this arithmetic sequence, as follows:

A(n)= -6 + (n-1) *(1/5)

A(₁)= -6 + (1 - 1) * (1/5) = -6 + (0) * (1/5) = -6

A(₄)= -6 + (4 - 1) * (1/5) = -6 + (3) * (1/5) = -6 +3/5 = -5 2/5

A(₁₀)= -6 + (10 - 1) * (1/5) = -6 + (9) * (1/5) = -6 + 9/5 = -4 1/5

<u>The correct answer is B. -6, -5 2/5, - 4 1/5</u>

7 0
3 years ago
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