A model rocket is launched from the ground with an initial velocity of 100 feet per second. How many seconds later does the rock
et hit the ground?
Enter your answer as a number rounded to the nearest tenth, such as: 42.5
Enter your answer as a number rounded to the nearest tenth, such as: 42.5
1 answer:
Answer:
6.3
Step-by-step explanation:
The rocket hits the ground at the same speed it left, only the velocity is downward, rather than upward. That is, the change in velocity is from +100 ft/s to -100 ft/s, a total change of 200 ft/s. The change in velocity is brought about by the acceleration due to gravity, 32 ft/s/s. The time required for the observed change in velocity is ...
(200 ft/s)/(32 ft/s²) = 6.25 s
Rounded to tenths, it takes the rocket 6.3 seconds to hit the ground.
_____
The equation for the ballistic motion of the rocket is ...
h(t) = -1/2·gt² +v0·t
where g is 32 ft/s² and v0 is 100 ft/s. A graph of this equation shows the rocket hits the ground at 6.25 seconds, as above.
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b)
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