Answer:
opo miss sorry di ko po Alam yan
sorry
po
To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
Answer:
43.83cm
Step-by-step explanation:
There are only two faces that are 25cm by 36cm, the top and the bottom face. Since, the ant, cannot move across the bottom face, we are left with the top face which is a rectangle. The shortest distance is through the diagonal.
Drawing a diagonal, you have two right-angled triangles. Bringing any out, we would need to know the length of the diagonal which is the hypotenuse of the right angle triangle. Using Pythagoras theorem:
(Hypotenuse)^2 = (opposite)^2 + (adjacent)^2
H^2 = 25^2 + 36^2
H^2 = 625 + 1296
H^2 = 1921
H = sqrt (1921)
H = 43.83 cm (to 2 d.p.)
H which represents the hypotenuse, that is the diagonal is the shortest distance. Hence, the shortest distance is 43.83cm.
Answer:
Step-by-step explanation:
6 + 3x = 2 ( 2 + x)
6 + 3x = 4 + 2x
3x - 2x = 4 - 6
x = - 2
Hope it helps :)
Answer:
0.837
Step-by-step explanation:
3850*4.65%=179.025
150/179.025=0.837
0.837