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aev [14]
2 years ago
15

Simprury20 s)26 600J​

Mathematics
1 answer:
earnstyle [38]2 years ago
5 0

Answer:

opo miss sorry di ko po Alam yan

sorry

po

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2x^3+2x^2-19x+20=0 find the roots of the polynomial equation
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How do I solve this
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so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=&#10;\begin{cases}&#10;-7\\&#10;1&#10;\end{cases}&#10;\\\\\\&#10;\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}&#10;\\\\\\&#10;x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
3 years ago
Dee Anna has a roast that weighs 5.5 pounds. The recipe she is using calls for a roast that is 80 ounces. How many ounces does s
Maslowich

Answer:

24

Step-by-step explanation:

well yea just trust me :)

6 0
3 years ago
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craig are some blueberries. he used 2/5 of the blueberries to make muffins. He ate 1/3 of the remainder. what fraction of the bl
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He ate 1/5 of the blueberries
5 0
3 years ago
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Find the volume of the solid generated by revolving the region bounded by
Rama09 [41]

Answer:

V =\dfrac{25\pi}{\sqrt{2}}

Step-by-step explanation:

given,

y=5√sinx

Volume of the solid by revolving

V = \int_a^b(\pi y^2)dx

a and b are the limits of the integrals

now,

V = \int_a^b(\pi (5\sqrt{sinx})^2)dx

V =25\pi \int_{\pi/4}^{\pi/2}sinxdx

\int sin x = - cos x

V =25\pi [-cos x]_{\pi/4}^{\pi/2}

V =25\pi [-cos (\pi/2)+cos(\pi/4)]

V =25\pi [0+\dfrac{1}{\sqrt{2}}]

V =\dfrac{25\pi}{\sqrt{2}}

volume of the solid generated is equal to V =\dfrac{25\pi}{\sqrt{2}}

4 0
3 years ago
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