What interval would be appropriate to graph the date
1 answer:
You might be interested in
Exponential laws
![x^{\frac{m}{n}}=\sqrt[n]{x^{m}}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%20)
so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)=![\sqrt[3]{m^{1}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%5E%7B1%7D%7D%20)
= ![\sqrt[3]{m}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bm%7D%20)
so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)=
Using the law of sines, it is found that the distance between the kite and the dog is of 284.77 meters.
<h3>What is the law of sines?</h3>Suppose we have a triangle in which:
- The length of the side opposite to angle A is a.
- The length of the side opposite to angle B is b.
- The length of the side opposite to angle C is c.
The lengths and the sine of the angles are related as follows:
For the situation described, we have that:
- The height is opposite to the angle of 42º.
- The 425 meters are opposite to the angle of 87º.
Hence:
Applying cross multiplication:
h = 284.77 meters.
More can be learned about the law of sines at brainly.com/question/25535771
#SPJ1