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aev [14]
3 years ago
9

paula says that she can draw an array with a total of 17 counters placed in 3 rows. is she correct? if she is, draw the array. i

f she is not, explain why not​
Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

She is not correct

Step-by-step explanation:

An array (in context of multiplication) is the representation of objects in rows and columns with same number of elements in each row and in each column.

e.g

0 0 0

2 2 2

3 3 3

is an array.

The total numbers(number of objects) in an array must be divisible by the number of rows and by number of columns.

According to the statement:

Paula can draw an array with a total of 17 counters placed in 3 rows. According to the definition of array, the total number of counters must be divisible by number of rows/columns to form the array. Since, in this case, the total number of counters(17) is not divisible by number of rows(3), the array cannot be formed.

Thus we can conclude that Paula is not correct. An array could have been formed if there were 18 counters in total.

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An architect built a scale model of a sports stadium using a scale in which 2 inches represents 30 feet. The height of the sport
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3. Sophie and Jackie each have a collection of baseball cards, Jackie has 5 more cards than
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Answer:

Sophie has 12.5 cards

Step-by-step explanation:

Let

x -----> number of cards Sophie has

y -----> number of cards Jackie has

we know that

x+y=30 -----> equation A  

y=x+5 -----> equation B

Solve by substitution

Substitute equation B in equation A and solve for x

x+(x+5)=30

2x=30-5

x=12.5 cards

Note I assume the problem was invented without taking into account the result, because the amount of cards should be a whole number

5 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Darina [25.2K]

Answer:

Given definite  integral as a limit of Riemann sums is:

\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

4 0
3 years ago
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