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kozerog [31]
4 years ago
15

Expand the logarithmic expression. log(b)squrt(13/73)

Mathematics
2 answers:
TEA [102]4 years ago
8 0
\log_b\sqrt{\dfrac{13}{73}}=\dfrac12\log_b\dfrac{13}{73}=\dfrac{\log_b13-\log_b73}2
alexandr402 [8]4 years ago
6 0

Answer:

\frac{log_b{13}-log_b{73}}{2}

Step-by-step explanation:

log_b{\sqrt{\frac{13}{73}}}

First we remove the square root

log_b({\frac{13}{73})^\frac{1}{2}}

As per log property we can move the exponent 1/2 before log

\frac{1}{2}log_b{\frac{13}{73}}

Now we apply log property to expand log (13/73)

log(a/b)= log(a) - log(b)

\frac{1}{2}log_b{13}-log_b{73}}

\frac{log_b{13}-log_b{73}}{2}


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