All categories

3 years ago

a circuit is supplied with 30 volts and the total circuit resistance is 3 ohms what the current through the circuit flowing

Mathematics

2 answers:

kolezko [41]3 years ago

4 0

Answer:

10 amps

Step-by-step explanation:

Ohm's law states

I = $\frac{V}{R}$

I is the current, V the voltage and R the resistance, thus

I = $\frac{30}{3}$ = 10

natulia [17]3 years ago

3 0

Answer:

The current is 10 amps

Step-by-step explanation:

This problem bothers Ohms law

Which states that the the current passing through a wire is directly proportional to the potential difference between the ends provided the temperature of the wire remains constant.

V= IR

Where I =the current in amp

V= voltage in volts

R= resistance in Ohms

Given that v= 30volts

R= 3 Ohms

Substituting our data into the equation we have

30= I*3

I=30/3

I= 10 amps

You might be interested in

What is 2 1/6 plus 3 and 1/4

Alex777 [14]

5 5/12

(2+3) 1/6 + 1/4=

5 5/12

5 0

3 years ago

A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radi

lisov135 [29]

<h2>Answer:</h2>

$\boxed{\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}$

<h2>Explanation:</h2>

<em>The height of the rider from the ground after the Ferris wheel</em> equals <em>the starting point is 15 feet off the ground </em><em>plus </em><em>the radius of the Ferris wheel </em><em>plus </em><em>the opposite side of the triangle ΔABC </em>(See figure below).<em> </em>Hence our goal is to find this side. We have the angle $11\pi /2=165^{\circ}$ , therefore the angle ∠BAC = 165° - 90° = 75°. So this side can be found using trigonometry:

$\overline{BC}=\overline{AB}sin(75^{\circ})=50sin(75^{\circ})=\frac{25}{2}(\sqrt{6}+\sqrt{2})$

Finally, the height is:

$H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+15+50 \\ \\ \boxed{H=\frac{25}{2}(\sqrt{6}+\sqrt{2})+65}$

6 0

3 years ago

Help plz due today and don't worry abt my answers

Elanso [62]

This is for the one with the green background :) I corrected a few of the errors that collided with the answers for the 3 qns you didn’t know. Hope this helps!!!

8 0

3 years ago

Evaluate the expression 9-3÷1/3+1 <br>A. 9 <br>B. 3 <br>C. 1 <br>D. 19

ikadub [295]

PEMDAS
P- none
E- none
M- none
D- (3/1/3=1)
AS- 9-1+1=9

The answer is A.

7 0

3 years ago

1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro

alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

$P(VISA \:| \:AE) = 15\%\\$

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

$P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}$

For the given problem it becomes

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}$

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\$

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0

3 years ago