Find the slope-intercept form of an equation of the line perpendicular to the graph of x – 3y = 5 and passing through (0, 6).
1 answer:
Answer:
y=-3x+6
Step-by-step explanation:
x-3y=5
y=1/3x-5/3
slope of perpendicular line is -3 (opposite reciprocals)
y=mx+b
x=0 and y=6
6=3x+b
6=3(0)+b
6=b
y=-3x+6
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Answer:
what is the question? please provide the question.
Answer:
Step-by-step explanation:
g(x) = 3x + 5
g(3) = 3(3) + 5
g(3) = 9 + 5
g(3) = 14
-----------------------
f(x) = 2x² + 3
f(g(3)) = 2(g(3)) + 3
f(14) = 2(14²) + 3
f(14) = 2(196) + 3
f(14) = 392 + 3
f(14) = 395
-----------------------------
f(g(3)) = 395
