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andreyandreev [35.5K]
3 years ago
8

B5%29%7D%7B3%7D%3D1%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bcross-multiplying%7D%7D%7B2%28x-4%29%28x%2B5%29%3D3%7D%20%5C%5C%5C%5C%5C%5C%202%28%5Cstackrel%7B%5Cmathbb%7Bfoil%7D%7D%7Bx%5E2%2Bx-20%7D%29%3D3%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bdistributing%7D%7D%7B2x%5E2%2B2x-40%7D%3D3%5Cimplies%20%5Cunderset%7B%5Ctextit%7Bstandard%20form%7D%7D%7B%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B2%7Dx%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B2%7Dx%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B-43%7D%3D0%7D" id="TexFormula1" title="\bf \cfrac{2}{3}(x-4)(x+5)=1\implies \cfrac{2(x-4)(x+5)}{3}=1\implies \stackrel{\textit{cross-multiplying}}{2(x-4)(x+5)=3} \\\\\\ 2(\stackrel{\mathbb{foil}}{x^2+x-20})=3\implies \stackrel{\textit{distributing}}{2x^2+2x-40}=3\implies \underset{\textit{standard form}}{\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-43}=0}" alt="\bf \cfrac{2}{3}(x-4)(x+5)=1\implies \cfrac{2(x-4)(x+5)}{3}=1\implies \stackrel{\textit{cross-multiplying}}{2(x-4)(x+5)=3} \\\\\\ 2(\stackrel{\mathbb{foil}}{x^2+x-20})=3\implies \stackrel{\textit{distributing}}{2x^2+2x-40}=3\implies \underset{\textit{standard form}}{\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-43}=0}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

x =  - 6 3/10

We need to show at least two of these in workings including one in simplified format.

x = - 63/10   (minus in front of whole fraction)  

mixed number form  x = -6 3/10   (is simplified answer)

decimal form  x  =  -6.3  (is simplified answer)

Step-by-step explanation:

Just in case you ever need to write these in ans search answers already answered in same format.

You can;

Go to upper right corner and click the three dots : another menu opens.

Click the summation sign (4th from left) : you are now in math mode until you deselect it (which sometimes happens automatically). Type a^{2} and it will look like a2 .

Note : the brackets { and } aren’t necessary when your exponent is a natural number between 0 and 9, both included.

However, when you want to type e.g. a15 , you need to place them, because otherwise you will get a15 .

it will look in same way as we are taught with a pen, its the stupid copy paste thing hit and miss if it works on messages here, Obviously it didnt work when i copied just now.

Adding a Range of Cells Using the Summation Button

The Summation button will copy a formula that calculates the sum of the selected numeric cells to the clipboard.

For alphanumeric cells, clicking the Summation button will concatenate the text of the selected cells.

Select the cells by dragging the mouse over the selected area or dragging while holding Alt.

On the Document tab, click Summation.

Position the insertion point in the total cell.

On the Home tab, click Paste.

The Equation bar displays the addition of all cells in the selection.

Note: Only Numeric cells can be summed. Alphanumeric cells will have their text concatenated.

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pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base
kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

We expect your answer is supposed to be Step 4.

7 0
3 years ago
Write (-3)^4 in standard form
Olenka [21]

Answer: 81

Step-by-step explanation: Because, (-3)^4=-3*-3*-3*-3=-(-81)=81

3 0
3 years ago
A certain quantity has a decade growth factor of 2.6. What is it’s yearly growth factor?
8090 [49]

Answer:

31.2

Step-by-step explanation:

3 0
3 years ago
No links or files, worth 25 points, please help!
zavuch27 [327]

Answer:

6

Step-by-step explanation:

2 to the power of 1 is 2, anything to the power of one is the original number itself. 3*2=6

3 0
2 years ago
Read 2 more answers
4.1(-7.93-4.39a)-4.6a
ki77a [65]

Answer:

−22.599a−32.513

Step-by-step explanation:

Distribute:

= (4.1) (−7.93) + (4.1) (− 4.39 a) + − 4.6 a

= − 32.513 + − 17.999 a + − 4.6 a

Combine Like Terms:

= −32.513 + − 17.999 a + − 4.6 a

= (− 17.999 a + −4.6 a) + (− 32.513)

= − 22.599 a + (− 32.513) = − 22.599 a − 32.513

3 0
3 years ago
Read 2 more answers
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