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andreyandreev [35.5K]
3 years ago
8

B5%29%7D%7B3%7D%3D1%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bcross-multiplying%7D%7D%7B2%28x-4%29%28x%2B5%29%3D3%7D%20%5C%5C%5C%5C%5C%5C%202%28%5Cstackrel%7B%5Cmathbb%7Bfoil%7D%7D%7Bx%5E2%2Bx-20%7D%29%3D3%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bdistributing%7D%7D%7B2x%5E2%2B2x-40%7D%3D3%5Cimplies%20%5Cunderset%7B%5Ctextit%7Bstandard%20form%7D%7D%7B%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B2%7Dx%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B2%7Dx%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B-43%7D%3D0%7D" id="TexFormula1" title="\bf \cfrac{2}{3}(x-4)(x+5)=1\implies \cfrac{2(x-4)(x+5)}{3}=1\implies \stackrel{\textit{cross-multiplying}}{2(x-4)(x+5)=3} \\\\\\ 2(\stackrel{\mathbb{foil}}{x^2+x-20})=3\implies \stackrel{\textit{distributing}}{2x^2+2x-40}=3\implies \underset{\textit{standard form}}{\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-43}=0}" alt="\bf \cfrac{2}{3}(x-4)(x+5)=1\implies \cfrac{2(x-4)(x+5)}{3}=1\implies \stackrel{\textit{cross-multiplying}}{2(x-4)(x+5)=3} \\\\\\ 2(\stackrel{\mathbb{foil}}{x^2+x-20})=3\implies \stackrel{\textit{distributing}}{2x^2+2x-40}=3\implies \underset{\textit{standard form}}{\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-43}=0}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

x =  - 6 3/10

We need to show at least two of these in workings including one in simplified format.

x = - 63/10   (minus in front of whole fraction)  

mixed number form  x = -6 3/10   (is simplified answer)

decimal form  x  =  -6.3  (is simplified answer)

Step-by-step explanation:

Just in case you ever need to write these in ans search answers already answered in same format.

You can;

Go to upper right corner and click the three dots : another menu opens.

Click the summation sign (4th from left) : you are now in math mode until you deselect it (which sometimes happens automatically). Type a^{2} and it will look like a2 .

Note : the brackets { and } aren’t necessary when your exponent is a natural number between 0 and 9, both included.

However, when you want to type e.g. a15 , you need to place them, because otherwise you will get a15 .

it will look in same way as we are taught with a pen, its the stupid copy paste thing hit and miss if it works on messages here, Obviously it didnt work when i copied just now.

Adding a Range of Cells Using the Summation Button

The Summation button will copy a formula that calculates the sum of the selected numeric cells to the clipboard.

For alphanumeric cells, clicking the Summation button will concatenate the text of the selected cells.

Select the cells by dragging the mouse over the selected area or dragging while holding Alt.

On the Document tab, click Summation.

Position the insertion point in the total cell.

On the Home tab, click Paste.

The Equation bar displays the addition of all cells in the selection.

Note: Only Numeric cells can be summed. Alphanumeric cells will have their text concatenated.

You might be interested in
Help helphelpherllplpeleplpglhler
IRINA_888 [86]
1.) 10² + 4 · (6 + 3) - (27 ÷ 9) - 6 = 127 
For these types of questions, try to think of it like, well since the last number is negative 6, let me try to get everything before it to equal 133 so it will end up being 127. :)

2.) ( \frac{3}{5}  -  \frac{1}{2} ) ÷ \frac{1}{2} + 1.6·(0.3 + 0.42)
= 1/10 ÷ 1/2 + 1.6 · (0.72)
= 1/5 + 1.152
= 1.352
Remember that dividing a fraction by a fraction is like multiplying the coefficient of the second one to the original one.

3.) 15 · 1/2 ÷ 3/4
Remember that product is multiplication and quotient is division.

4.) \frac{(54 \frac{3}{10} - 11 \frac{7}{10}) }{3}
Remember that difference is subtraction and separating into three parts is like dividing it into three parts.


Hope this helped and ask me for further explanation! ^-^
5 0
4 years ago
Answer quick find the coordinates
Mekhanik [1.2K]

Answer:

  (-4, -3), (4, -1), (8, 0), (12, 1)

Step-by-step explanation:

The x- and corresponding y-values are listed in the table. Put each pair in parentheses, <em>x-value first</em>. (That is an <em>ordered pair</em>.)

  (x, y) = (-4, -3) . . . . from the first table entry

  (x, y) = (4, -1) . . . . from the second table entry

  (x, y) = (8, 0) . . . . from the third table entry

  (x, y) = (12, 1) . . . . from the last table entry

3 0
4 years ago
1. Is it proportional?
astra-53 [7]

Answer:

Y=5(x) Yes it is porportional.

Step-by-step explanation:

So lets look at the graph.

We first have 1x = 5y

Well, that makes it seem like for each x there are 5 y.

Lets see the other values:

2x = 10y

Divide both sides by 2 tog et x alone:

1x=5y

Again, for each x, there are 5y.

This is true for each one:

3x=15y

=

1x=5y

4x=20y

=

1x=5y

5x=25y

=

1x=5y

and finally:

6x=30y

=

1x=5y.

So yes, this is poroportional.

It can be shown as x=5y, since for a single x, there are 5 y's.

Hope this helps!

5 0
3 years ago
I need help finding the solution
Ilya [14]
<h3>Answer:  226 degrees</h3>

=====================================================

Explanation:

Notice the tickmarks on the segments in the diagram. This tells us that chords DC and CB are the same distance from the center. It furthermore means that DC and CB are the same length, and arcs DC and CB are the same measure

arc DC = arc CB

12x+7 = 18x-23

12x-18x = -23-7

-6x = -30

x = -30/(-6)

x = 5

---------------------

Use this x value to find the measure of arcs DC and CB

  • arc DC = 12x+7 = 12*5+7 = 67
  • arc CB = 18x-23 = 18*5-23 = 67

We get the same measure for each, which helps confirm we have the correct x value.

The two arcs in question add to 67+67 = 134 degrees. This is the measure of arc DCB. Subtract this from 360 to get the answer

arc DAB = 360-(arc DCB) = 360-134 = 226 degrees

I'm using the idea that (arc DCB) + (arc DAB) = 360 since the two arcs form a full circle.

7 0
3 years ago
Which of the following formulas can be used to calculate the area of a circle? A. 2πr B. length • width C. π2r D. πr2
Kryger [21]

Answer:

The area of a circle is = pi * radius^2

or

= \pi * radius^{2}

Step-by-step explanation:

It looks like you may have left out the exponent or "^" symbol.

8 0
3 years ago
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