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andreyandreev [35.5K]
3 years ago
8

B5%29%7D%7B3%7D%3D1%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bcross-multiplying%7D%7D%7B2%28x-4%29%28x%2B5%29%3D3%7D%20%5C%5C%5C%5C%5C%5C%202%28%5Cstackrel%7B%5Cmathbb%7Bfoil%7D%7D%7Bx%5E2%2Bx-20%7D%29%3D3%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bdistributing%7D%7D%7B2x%5E2%2B2x-40%7D%3D3%5Cimplies%20%5Cunderset%7B%5Ctextit%7Bstandard%20form%7D%7D%7B%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B2%7Dx%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B2%7Dx%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B-43%7D%3D0%7D" id="TexFormula1" title="\bf \cfrac{2}{3}(x-4)(x+5)=1\implies \cfrac{2(x-4)(x+5)}{3}=1\implies \stackrel{\textit{cross-multiplying}}{2(x-4)(x+5)=3} \\\\\\ 2(\stackrel{\mathbb{foil}}{x^2+x-20})=3\implies \stackrel{\textit{distributing}}{2x^2+2x-40}=3\implies \underset{\textit{standard form}}{\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-43}=0}" alt="\bf \cfrac{2}{3}(x-4)(x+5)=1\implies \cfrac{2(x-4)(x+5)}{3}=1\implies \stackrel{\textit{cross-multiplying}}{2(x-4)(x+5)=3} \\\\\\ 2(\stackrel{\mathbb{foil}}{x^2+x-20})=3\implies \stackrel{\textit{distributing}}{2x^2+2x-40}=3\implies \underset{\textit{standard form}}{\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-43}=0}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
adell [148]3 years ago
6 0

Answer:

x =  - 6 3/10

We need to show at least two of these in workings including one in simplified format.

x = - 63/10   (minus in front of whole fraction)  

mixed number form  x = -6 3/10   (is simplified answer)

decimal form  x  =  -6.3  (is simplified answer)

Step-by-step explanation:

Just in case you ever need to write these in ans search answers already answered in same format.

You can;

Go to upper right corner and click the three dots : another menu opens.

Click the summation sign (4th from left) : you are now in math mode until you deselect it (which sometimes happens automatically). Type a^{2} and it will look like a2 .

Note : the brackets { and } aren’t necessary when your exponent is a natural number between 0 and 9, both included.

However, when you want to type e.g. a15 , you need to place them, because otherwise you will get a15 .

it will look in same way as we are taught with a pen, its the stupid copy paste thing hit and miss if it works on messages here, Obviously it didnt work when i copied just now.

Adding a Range of Cells Using the Summation Button

The Summation button will copy a formula that calculates the sum of the selected numeric cells to the clipboard.

For alphanumeric cells, clicking the Summation button will concatenate the text of the selected cells.

Select the cells by dragging the mouse over the selected area or dragging while holding Alt.

On the Document tab, click Summation.

Position the insertion point in the total cell.

On the Home tab, click Paste.

The Equation bar displays the addition of all cells in the selection.

Note: Only Numeric cells can be summed. Alphanumeric cells will have their text concatenated.

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Which table could be used to graph a piece of the function?
Darya [45]

Answer:b

Step-by-step explanation:

6 0
3 years ago
Graph the data in the table below. Which kind of function best models the data? write an equation to model the data.
harina [27]

Answer:

A quadratic function.

y=2.5x^{2}

Step-by-step explanation:

If you plot the points given in the table, you obtain the graph shown in the figure attached.

As you can see, it is a parabola, therefore, the function that best models the data is a quadratic function.

By definition, the parent function of a quadratic function is:

y=x^{2}

You can compress or stretch it in the y-direction by multiplying the function by a constant C:

 y=Cx^{2}

If 0, then the function is compressed.

If C>1, then the function is stretched.

You can find the constant of the function asked as following:

- Substitute x=1 into the parent function to obtain the y-coordinate:

y=(1)^{2}=1

Then the point is (1,1)

- As you can see, with x=1 you obtain y=1 in the parent function, and in the function given in the table when x=1, y=2.5, therefore, the function is multiplied by 2.5. Therefore the constant is:

C=2.5

Then the function is:

y=2.5x^{2}

7 0
3 years ago
What is 30% of 75?<br> A. 250<br> B. 22.5<br> C. 25<br> D. 225
AURORKA [14]
22.5 is your answer
3 0
3 years ago
Read 2 more answers
A bridge spans a distance of 1012m. Large cables are attached to the tops of the towers, 45 m above the road. The road is suspen
Dovator [93]

Answer:

A quadratic equation for the large cables is f(x) = \dfrac{87 }{512072} \cdot x^2 + 1.5

Step-by-step explanation:

The shape of the quadratic equation representing the large cables is a parabola

Taking the point of the smallest vertical cables as the vertex, (h, k) with coordinates, (0, 1.5), we have;

h = -b/(2·a)

∴ 0 = -b/(2·a), from which we have, b = 2·a × 0 = 0

k = 1.5 = c - (b²/(4·a) = c - (0/(4·a)) = c

∴ c = 1.5

The standard form of the quadratic equation, a·(x - h)² + k is therefore, given as follows;

f(x) = a·(x - 0)² + 1.5 = a·x² + 1.5

At the towers which are on either side of the bridge, when x = 1012/2 = 506, f(x) = y = 45

Therefore, we have;

45 = a·506² + 1.5

a = (45 - 1.5)/506² = 87/512072 ≈ 1.699 × 10⁻⁴

The quadratic equation for the large cables, f(x), can therefore be presented as follows;

f(x) = \dfrac{87 }{512072} \cdot x^2 + 1.5

3 0
3 years ago
Can someone please help me please
NemiM [27]

Answer:

It should also be 63°

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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