If I’m analyzing the question correct, you would pay 912 in total
Answer:
Jasmine ran last week 37.2 miles
Step-by-step explanation:
Let
x ----> number of miles Rob ran last week
y ----> number of miles Jasmine ran last week
we know that
x=y-27.2 ----> equation A
x=10 ----> equation B
Substitute equation B in equation A and solve for y
10=y-27.2
y=10+27.2
y=37.2 miles
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
D. The independent variable is the number of ticket price increases, and the dependent variable is the ticket sales.
Step-by-step explanation:
The wording, "the table shows A <em>with respect to</em> B" means that "B" is the independent variable. Here, "B" is "the number of times they have increased the price of the ticket." That is ...
the independent variable is the number of ticket price increases
Answer: I think its C
Step-by-step explanation: