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mote1985 [20]
3 years ago
9

What’s the correct answer for this question?

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

C:

Step-by-step explanation:

Both angles add up to 180°

<BCG + <BFG = 180°

2x+146+4x+238=180

6x+384 = 180°

6x = 180-384

6x = -204

Dividing both sides by 6

x = -34

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Someone who actually knows what they doing please ‍♀️
mariarad [96]

Answer:

5/9 (F-32) = 25

Step-by-step explanation:

5/9 (F-32) = C

Multiply each side by 9/5

5/9 * 9/5 (F-32) =9/5 C

F -32 = 9/5 C

Add 32

F -32 +32 = 9/5 C +32

F = 9/5 C +32

We want 25 C to Fahrenheit

F = 9/5 *25 +32

F = 9*5 +32

F = 45+32

F = 77

5 0
3 years ago
What diretction does the parabola open if its equatin is y=-4(x+2)^2
Fed [463]
It is a cap-size parabola. The parabola "goes down". The graph of this function looks like in this attached picture. 

5 0
2 years ago
Math help please i will mark brainliest!!!!!
mel-nik [20]

Answer:

The second choice is the correct one.

Step-by-step explanation:

20x^4 - 45x^2

GCF is 5x^2, so the factors are:

5x^2( 4x^2 - 9)

Now 4x^2 - 9 is the differencr of 2 squares:

4x^2 - 9 = (2x + 3)(2x - 3)>

4 0
3 years ago
The meat department of a local supermarket packages ground beef using meat trays of two sizes: 1 designed to hold 1 lb of meet a
r-ruslan [8.4K]

Answer:

c) 0.932

99% confidence interval for average weights of all packages sold in small meat trays.

(0.932 ,1.071)

Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation  of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

<u>The 99% confidence intervals are given by</u>

(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )

The degrees of freedom γ=n-1 =35-1=34

tₐ =  2.0322

99% confidence interval for average weights of all packages sold in small meat trays

(1.01 - 2.0322 \frac{0.18}{\sqrt{35} } , 1.01+2.0322 \frac{0.18}{\sqrt{35} } )

( 1.01 - 0.06183 , 1.01+0.06183)

(0.932 ,1.071)

<u>Final answer</u>:-

<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>

<u>(0.932 ,1.071)</u>

5 0
3 years ago
Someone help ASAP!!!!!!
Alchen [17]

Answer:

Length, l = 11 ft.

Width, w = 9 ft.

Step-by-step explanation:

From the given data, the area of the rectangle = 99 ft².

Area of the rectangle = Length, l X Width, w

Here, Length, l = 7 more than twice the width

⇒       Length, l = 7 + 2w

Therefore, Area, A = 99 = (7 + 2w)w

⇒ 99 = 7w + 2w²

⇒ 2w² + 7w - 99 = 0

Solve the Quadratic equation using the formula: x = $ \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $ for the quadratic equation ax² + bx + c = 0.

Therefore, w = $ \frac{-7 \pm \sqrt{7^2 -4(2)(-99)}}{2(2)} $

$ = \frac{-7 \pm \sqrt{49 + 8(99)}}{4} $

$ = \frac{-7 \pm + \sqrt{841}}{4} $

Since, $ \sqrt{841} = 29 $ we get:

$ w = \frac{-7 \pm 29}{4} $

This gives two values of 'w', viz., w = $ \frac{-7 - 29}{4} $, $ \frac{-7 + 29}{4} $

$ \implies w = \frac{22}{4}, \frac{-36}{4} $

⇒ w = $ \frac{22}{4} $, -9.

We take the integer values.

If w = -9, then l = 2(-9) + 7

⇒ l = - 18 + 7 = - 11

Therefore, the length, l of the rectangle = - 11 ft.

and the width, w of the rectangle = - 9 ft.

Hence, the answer.

3 0
2 years ago
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