Answer:
58
Step-by-step explanation:
All three angles of a triangle have to add up to 180. Given this we can do the following problem:
180-34-88 = 58
You could use a calculator. Other than that, I've never heard of an easier way to do long division.
Answer:
-3
Step-by-step explanation:
woiowiowiwowiowiwooiwoiwowiw
Answer:
B
Step-by-step explanation:
An equation of a circle:
(x - a)² + (y - b)² = r²
(a; b) - a coordinates of a center
r - a radius
r = 5; P(6; 1) ⇒ a = 6 and b = 1
therefore
(x - 6)² + (y - 1)² = 5²
check:
A) Q(1; 11)
L = (1 - 6)² + (11 - 1)² = (-5)² + 10² = 25 + 100 = 125
R = 25
L ≠ R
B) R(2; 4)
L = (2 - 6)² + (4 - 1)² = (-4)² + 3² = 16 + 9 = 25
R = 25
L = R - CORRECT
C) S(4; -4)
L = (4 - 6)² + (-4 - 1)² = (-2)² + (-5)² = 4 + 25 = 29
R = 25
L ≠ R
D) T(9; -2)
L = (9 - 6)² + (-2 - 1)² = 3² + (-3)² = 9 + 9 = 18
R = 25
L ≠ R
Answer: B) R(2; 4).
Answer:
Not enough information to solve for one set of fractions that add to 35. See below.
Step-by-step explanation:
Let M and N be the 2 denominators.
We are told that both fractions have 1 as their numerator. That means our factions are:
1/M and 1/N
We are told that (1/M + 1/N) = 35
But without any more information, I don't see how this could be solved.
For example, if M = 0.1:
(1/M + 1/N) = 35
(1/0.1 + 1/N) = 35
(10 + 1/N) = 35
1/N = 25
N = 1/25
------
(1/M + 1/N) = 35
(1/0.1 + 1/(1/25)) = 35
(10 + 25) = 35
But if M = 0.01,
(1/M + 1/N) = 35
(1/0.01 + 1/N) = 35
100 + 1/N = 35
1/N = -75
N = -(1/75)
Both are valid, as many (infinite) others.
