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mestny [16]
3 years ago
6

I need help please help me

Mathematics
1 answer:
jonny [76]3 years ago
8 0

Answer:

SSS

Step-by-step explanation:

ST = YA, SY = TA Given

AS = SA Reflexive property

ΔSTA ≅ ΔAYS SSS

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Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
otez555 [7]

We can write the function in terms of y rather than h(x) so that:

y = 3 (5)^x

 

A. The rate of change is simply calculated as:

r = (y2 – y1) / (x2 – x1) where r stands for rate

 

Section A:

rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)

rA = 12

 

Section B:

rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)

rB = 300

 

B. We take the ratio of rB / rA:

rB/rA = 300 / 12

rB/rA = 25

 

So we see that the rate of change of section B is 25 times greater than A

7 0
3 years ago
The cake density is 0.454 ounce per cubic inch and the fair price is $0.20 per ounce. What should be a fair price for each cake?
aleksklad [387]

Answer:

price = x * 0.2

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price = x * 0.454 * 0.2

Step-by-step explanation:

In this case we must know either the mass of the cake or its volume.

Given the case that we know the mass of the cake, it would be:

price = x * 0.2

where x is the mass of the cake in ounces, that is to say if for example a cake has a mass of 10 ounces, it would be:

price = 10 * 0.2 = 2

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Given the case of the volume, we must first multiply the density by this volume in order to calculate the mass and finally the price.

price = x * 0.454 * 0.2

where x is the volume of the cake in cubic inches, if for example the volume is 10 cubic inches it would be:

price = 10 * 0.454 * 0.2 = 0.908

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Answer:

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There are 14 values above. The mean of these 14 numbers is calculated by dividing their sum by 14 which will give us an answer of 117.07 or ~117. The smallest of these values is 69 which is 48 units to the left of the average. The largest value is 189 which is 72 units to the right of the average. Therefore, in this distribution, the values are skewed to the right. 
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In a right triangle abc, cd is an altitude, such that ad=bc. Find ac, if ab=3 cm, and cd= square root 2 cm.
Mashcka [7]

      <u>ΔACB</u>                                               <u>ΔCDA</u>

AC² + BC² = AB²                           AD² + CD² = AC²  

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                         (3)² + (√2)² = 2AC²            (AB=3 and CD=√2 were given)

                          9  +   2    = 2AC²

                               11        = 2AC²

                                \frac{11}{2}        = AC²

                                \sqrt{\frac{11}{2} }     = AC

                                \frac{11\sqrt{2} }{2}      = AC

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3 years ago
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