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3 years ago

I need help please help me

Mathematics

1 answer:

jonny [76]3 years ago

8 0

Answer:

SSS

Step-by-step explanation:

ST = YA, SY = TA Given

AS = SA Reflexive property

ΔSTA ≅ ΔAYS SSS

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Please help me! ASAP explain for brainlist.

LekaFEV [45]

Step-by-step explanation:

Hello,

First, there are 8 possible outcomes for the game spinner.

Second, the spinner is on 5, meaning that the outcome is 5.

Try to work with this, and if you need more help, I’ll answer back if I can.

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2 years ago

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Sorry there is a few pics please help

Sever21 [200]

Answer:

Step-by-step explanation:

In the graph, there are only two values for a graph. In this case, those two values are crackers and calories.

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3 years ago

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If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

Which ordered pair represents a solution to the inequality 3x - y < -5?A. (2, -15)B. (1, 10)C. (2, 11)D. (3, 12)

White raven [17]

Answer:

(2,11)

Step-by-step explanation:

what i did was actually substitution

It's like ..what I do when I've forgotten how to solve a particular equation in math or even physics

But I'd recommend you find the real solution cuz there's a formula

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ella [17]

The random nature of the process is why Gina doesn't get the theoretical probability. If she were to repeat this experiment say 1000 or perhaps 10,000 times, then her experimental probability value should get closer to 1/2. It likely won't land *exactly* on 1/2 because again of the random nature of the outcomes.

For more information, check out the Law of Large Numbers.

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