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4 years ago

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Jogger A and Jogger B start at the same point. Jogger A travels 0.9 miles due east, then turns 120° clockwise, then travels anot

her 3 miles. Jogger B travels 0.9 miles due west, then turns 115° counterclockwise, then travels another 3 miles. Do the joggers end up in the same place? Explain.

1 answer:

MatroZZZ [7]4 years ago

8 0

No they dont because jogger A turns 5 degrees more than jogger B and jogger B turned at 115 degrees.

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Mr. F is buying 8 computers for the computer lab. if one computer costs $1,156, How much will the computers cost in all?

Andreas93 [3]

answer: $9248

explanation:

well, we know the cost for one, so if each computer costs the same, multiply the cost of one of them by 8 to get the total.

8 x 1,156 = 9248.

so, we can assume this is what the computers will cost in total because there seems to be no added tax or fees.

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3 years ago

Two positive integers are 3 units apart on a number line. Their product is 108. Which equation can be used to solve for m, the g

nikitadnepr [17]

If the greater integer is m, then the smaller integer must be (m-3) because the integers are 3 units apart on a number line. It cannot be in front of m, because m is the greater so it must be behind m meaning it is 3 units less. Product is the technical term for the result of a multiplication problem so m(m-3) = 108 would be the answer.

Final Answer: m(m-3) = 108

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3 years ago

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Write the number in expanded form 249,104,330

olga2289 [7]

200,000,000 + 40,000,000 + 9,000,000 + 100,000 + 4,000 + 300 + 30

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3 years ago

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A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January

Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that $p = 0.23$

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109$

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116$

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

$E(X) = np = 10*0.23 = 2.3$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33$

The expected number is 2.3 and the standard deviation is 1.33.

5 0

3 years ago

Please help! Will give brainiest (if i can) if you answer.

german

Answer:

A

Step-by-step explanation:

5 0

3 years ago