9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
Answer:
Starts at 6:15
Note: An hour is 60 minutes.
So an hour after 6:15 is 7:15 and an hour after that is 8:15. Now just add another 10 minutes and you get 8:25.
So the film ended at 8:25.
2(x + 2) + 2 = 2(x + 3) + 1
2x + 4 + 2 = 2x + 6 + 1
2x + 6 = 2x + 7 - NO SOLUTION
(subtract 2x from both sides, then 6 = 7 FALSE)
2x + 3(x + 5) = 5(x – 3)
2x + 3x + 15 = 5x - 15
5x + 15 = 5x - 15 - NO SOLUTION
4(x + 3) = x + 12
4x + 12 = x + 12 - ONE SOLUTION
4 – (2x + 5) = (–4x – 2)
4 - 2x - 5 = -4x - 2
-2x - 1 = -4x - 2 - ONE SOLUTION
5(x + 4) – x = 4(x + 5) – 1
5x + 20 - x = 4x + 20 - 1
4x + 20 = 4x + 19 - NO SOLUTION
C. $135, 1/4 of 60 is 15 and add that on top of 60x2
Find the missing angles using either the triangle sum theorem (a2+b2=c2) or inverse trigonometric ratios
