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kvasek [131]
3 years ago
12

Okay so 1/4 of __ = 31 ?

Mathematics
2 answers:
Sophie [7]3 years ago
7 0

Answer:

124

Step-by-step explanation:

31 * 4 = 124

124 * 1/4 = 31

k0ka [10]3 years ago
3 0
124
31 * 4 = 124
or
1/4x = 31 and simplify both sides of the equation and isolate the variable
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1). Solve for n n - 63 = 126 *
Zinaida [17]

Answer:

n=189

Step-by-step explanation:

n-63=126\\n=126+63\\n=189

I hope this helps! :)

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Maria believes she will get 1 hit in 20% of her softball games, 2 hits in 25% of her games, 3 hits in 50% of her games, and 4 hi
Makovka662 [10]
I would put 2 as the answer
4 0
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2. Write the inequality and show all work to solve the
seraphim [82]
Yes you are doing it correctly.
$12.00 + $3.00x <= $24.00
$12.00 + $3.00x - $12.00 <= $24.00 - $12.00
$3.00x <= $12.00
$3.00x/$3.00 <= $12.00/$3.00
x <= 4

The number line representation will be an arrow with a shaded round head pointing to the left from tne number 4.
6 0
3 years ago
Write two subtraction facts related to 7 +5=12
Lilit [14]

There are different ways you can write these numbers all you do is go by what the number says and think about it.

EX1) 12-5=7

EX2) 12-7=5

5 0
3 years ago
Read 2 more answers
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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