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2 years ago

A shape is rotated counterclockwise 110 degrees about the origin. What is another way to describe the rotation?

Mathematics

1 answer:

Kitty [74]2 years ago

6 0

At max a rotation can be equal to π or 180°

So if it's rotated 110° counterclockwise then it's equal to rotation of supplementary angle clockwise

Supplementary angle=180-110=70°

70° rotation clockwise

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Describe one way in which the usage of vertex-edge graphs apply to you

LuckyWell [14K]

Answer:

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3 years ago

Simplify the expression fraction with numerator of the square root of negative one and denominator of the quantity three plus ei

Ainat [17]

The right answer for the question that is being asked and shown above is that: "fraction with numerator negative 3 minus i and denominator 10." This is the simplified expression fraction with numerator of the square root of negative one and denominator of the quantity three plus eight times i minus the <span>quantity two plus five times i.</span>

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3 years ago

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A salesperson works 40 hours per week at a job where she has two options for being paid. Option A is an hourly wage of $27. Opt

saul85 [17]

Answer:

1 week

Step-by-step explanation:

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3 years ago

Help mi out plz..... solve using matrix method

HACTEHA [7]

Answer:

x = $\frac{22}{7}$

y = $\frac{3}7}$

Step-by-step explanation:

$2x-3y=5\\5x=4y=14\\\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] =\left[\begin{array}{c}5\\14\\\end{array}\right]$

Let A = $\\\left[\begin{array}{cc}2&-3\\5&-4\\\end{array}\right]$

The inverse of A multiplied by A = the identity matrix $\left[\begin{array}{cc}1&0\\0&1\\\end{array}\right]$

Inverse of A = $\frac{1}{detA}$ $\left[\begin{array}{ccc}-4&3\\-5&2\\\end{array}\right]$

detA = ad - bc = $-8 - - 15 = 7$

Inverse of A = $\left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{cc}\frac{-4}{7} &\frac{3}{7} \\\frac{-5}{7} &\frac{2}{7}\\\end{array}\right] \left[\begin{array}{ccc}5\\14\\\end{array}\right] = \left[\begin{array}{ccc}\frac{22}{7} \\\frac{3}{7} \\\end{array}\right]$

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3 years ago

Write in standard form 2+4i over 1+i

Levart [38]

So hmm a conjugate, is pretty much just, the same binomial, but with a different sign in the middle, so, a + b, has a conjugate of a - b
or -a + b, has a conjugate of - a - b, or c - d, has a conjugate of c +d, and so on

anyway, the idea being, to "rationalize" the expression, namely, getting rid of the pesky radical in the denominator

so, we'll multiply the expression by 1, since anything times 1 is just itself

however, bear in mind, that 1, can be a/a, or b/b, or cheese/cheese, or anything/anything

so, we'll multiply the top and bottom of the fraction, by the conjugate of the denominator

anyhow, that said $\bf \cfrac{2+4i}{1+i}\cdot \cfrac{1-i}{1-i}\implies \cfrac{(2+4i)(1-i)}{(1+i)(1-i)}\implies \cfrac{2-2i+4i-4i^2}{1-i^2}\\\\
-----------------------------\\\\
\textit{recall that }i^2=-1\\\\
-----------------------------\\\\
 \cfrac{2-2i+4i-4(-1)}{1-(-1)}\implies \cfrac{2+2i+4}{2}\implies \cfrac{6+2i}{2}\implies \cfrac{6}{2}+\cfrac{2i}{2}
\\\\\\
\boxed{3+i}$

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2 years ago