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kvasek [131]
3 years ago
10

How do you solve for this?

Mathematics
1 answer:
tankabanditka [31]3 years ago
3 0
I hope this helps you


m (I)= m (P)


3x+4=72-x

4x=68

x= 17
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Factor by Grouping.
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Answer:

The ac product of 35x^2+41x+12 is <u>420</u>.

The factors of the ac product that add to 41 are <u>20</u> and <u>21</u>.

35x^2+41x+12 = (7x+4)(5x+3)

Step-by-step explanation:

1) The general form of a quadratic is ax^2 + bx + c. Hence, multiplying 35 by 12 gives you the product of ac, which is 420.

2) We need to find two numbers that multiply to 420 and add up to 41 <u>simultaneously</u>. If we pull out the factors of 420, two of them will be 20 and 21, which multiply to 420 as well as add up to 41.

3) Write 41x as a sum.

35x^2+20x+21x+12

Now, we can factor them out by grouping.

35x^2+20x+21x+12\\5x(7x+4)+3(7x+4)

Since, 7x +4 is common in both of the factors, we only take one of the 7x+4 along with 5x and 3.

(7x+4)(5x+3)

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This is how it would look like:

-2x + 5x - 3x - 4x -7 - 6\\=3x - 3x - 4x - 13\\= -4x - 13

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