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V125BC [204]
2 years ago
12

4x−4<8 AND 9x+5>23 Doing Khan Academy HelP!!

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
5 0

Answer:

x<3 and x>2

Step-by-step explanation:

write the symbols this < and > to get the correct answer

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30 + 40 1- 40 = 69

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3 years ago
Write in standard form the equation of a line with a slope of -3/5 and a y intercept of -3
Vlada [557]

Answer:

5y+3x=-9

Step-by-step explanation:

Let us start by the general form of the standard equation, Ax+By=C. One way we can solve this problem is by finding the <u>slope-intercept form</u> of this equation, y=mx+b, and converting it into the standard equation. In the slope-intercept form, m represents the slope, b represents the y intercept.

From this problem, we are given both the slope and the y intercept. We know have the equation:

y=-\frac{3}{5}x -3

Great! Now let us rearrange the terms so that the y and x terms are on one side of the equation.

y+\frac{3}{5} x=-3

This seems right, but a standard equation must have coefficient values that are real numbers. So, A and B must be real numbers. We can do this by multiplying the entire equation by 5 and ridding the denominator of the A term.

5y+3x=-9

<em>I hope this helps! Please let me know if you have any questions :)</em>

7 0
3 years ago
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3 years ago
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Step-by-step explanation:

O

3x² - 11x - 4 = 0

a = 3 ; b = -11 , c = -4

Sum \ of \ roots = \dfrac{-b}{a}=\dfrac{-(-11)}{3}=\dfrac{11}{3}\\\\Product \ of \ roots =\dfrac{c}{a}=\dfrac{-4}{3}\\\\

W

8x² + 12x = -1

8x² + 12x + 1 = 0

a = 8 ;  b = 12 ; c = 1

Sum  \ of \ roots =\dfrac{-b}{a}=\dfrac{-12}{8}=\dfrac{-3}{2}\\\\Product \ of \ roots = \dfrac{c}{a}=\dfrac{1}{8}

L

x² + x = 6

x² + x - 6 = 0

a = 1 ; b= 1 ; c = -6

Sum \ of \ roots = \dfrac{-1}{1}=-1\\\\Product \ of \ roots = \dfrac{-6}{1}=-6

G

x²- 2x - 2 =0

a = 1 ; b = -2 ; c = -2

Sum \ of \ roots = \dfrac{-(-2)}{1}=2\\\\Product \ of \ roots = \dfrac{-2}{1}=-2

E

4x - 5 = -4x²

4x² + 4x - 5 = 0

a = 4 ;  b = 4 ; c = -5

Sum \ of \ roots = \dfrac{-4}{4}=-1\\\\Product \ of \  roots=\dfrac{-5}{4}

B

12x² +x -6 = 0

a = 12 ; b = 1 ; c = -6

Sum \ of \ roots =\dfrac{-1}{12}\\\\Product \ of \ roots  =\dfrac{-6}{12}=\dfrac{-1}{2}

R

2x² + 5x - 25 = 0

a = 2 ; b = 5 ; c = -25

Sum \ of \ roots=\dfrac{-5}{2}\\\\Product \ of \ roots =\dfrac{-25}{2}

A

6x² -5x - 4 = 0

a = 6 ; b = -5 ; c = -4

Sum \ of \ roots =\dfrac{-[-5]}{6}=\dfrac{5}{6}\\\\Product \ of \ roots = \dfrac{-4}{6}=\dfrac{-2}{3}

8 0
2 years ago
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D) The measures of the non- right angles in each triangle .
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