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Mashutka [201]
3 years ago
15

Find the GCF of 21m^5n^2 and 28m^4n2

Mathematics
1 answer:
nikklg [1K]3 years ago
7 0

Answer: <em>7m⁴n²</em>

Step-by-step explanation:

<em>Find the GCF of 21m⁵n² and 28m⁴n².</em>

<em>Find the prime factors of each term in order to find the greatest common factor (GCF).</em>

<em>21m⁵n² = </em><em><u>7</u></em><em> · 3 · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · m · </em><em><u>n</u></em><em> · </em><em><u>n</u></em>

<em>28m⁴n² = </em><em><u>7</u></em><em> · 2 · 2 · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>n</u></em><em> · </em><em><u>n</u></em>

<em>The product of these common prime factors will be  the Greatest Common Factor: </em><em><u>7</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>m</u></em><em> · </em><em><u>n</u></em><em> · </em><em><u>n</u></em><em> = 7m⁴n²</em>

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