The probability that it also rained that day is to be considered as the 0.30 and the same is to be considered.
<h3>
What is probability?</h3>
The extent to which an event is likely to occur, measured by the ratio of the favorable cases to the whole number of cases possible.
The probability that the temperature is lower than 80°F and it rained can be measured by determining the number at the intersection of a temperature that less than 80°F and rain.
So, This number is 0.30.
Hence, we can say that it was less than 80°F on a given day, the probability that it also rained that day is 0.30.
To learn more about the probability from the given link:
brainly.com/question/18638636
The above question is incomplete.
The conditional relative frequency table was generated using data that compared the outside temperature each day to whether it rained that day. A 4-column table with 3 rows titled weather. The first column has no label with entries 80 degrees F, less than 80 degrees F, total. The second column is labeled rain with entries 0.35, 0.3, nearly equal to 0.33. The third column is labeled no rain with entries 0.65, 0.7, nearly equal to 0.67. The fourth column is labeled total with entries 1.0, 1.0, 1.0. Given that it was less than 80 degrees F on a given day, what is the probability that it also rained that day?
#SPJ4
Assuming the numbers are percents, the answer is 25%, because 5/20 is 1/4, then convert the fraction to a percentage and you get 25%.
Answer:
0.36878
Step-by-step explanation:
Given that:
Mean number of miles (m) = 2135 miles
Variance = 145924
Sample size (n) = 40
Standard deviation (s) = √variance = √145924 = 382
probability that the mean of a sample of 40 cars would differ from the population mean by less than 29 miles
P( 2135 - 29 < z < 2135 + 29)
Z = (x - m) / s /√n
Z = [(2106 - 2135) / 382 / √40] < z < [(2164 - 2135) / 382 / √40]
Z = (- 29 / 60.399503) < z < (29 / 60.399503)
Z = - 0.4801364 < z < 0.4801364
P(Z < - 0.48) = 0.31561
P(Z < - 0.48) = 0.68439
P(- 0.480 < z < 0.480) = 0.68439 - 0.31561 = 0.36878
= 0.36878
Answer:
- 6.04 km (per angle marks)
- 5.36 km (per side hash marks)
Step-by-step explanation:
Going by the angle indicators, the ratios of corresponding sides of the similar triangles are ...
x/2000 = 4200/3500
x = 2000·6/5 = 2400 . . . . yards
Then the distance of interest is ...
(2400 yd + 4200 yd)×(0.0009144 km/yd) = 6.6×.9144 km
= 6.03504 km ≈ 6.04 km
_____
Going by the red hash marks, the ratios of corresponding sides of the similar triangles are ...
x/2000 = 3500/4200
x = 2000·(5/6) = 5000/3 . . . . yards
Then the distance of interest is ...
(5000/3 + 4200) yd × 0.0009144 km/yd ≈ 5.36 km
_____
<em>Comment on the figure</em>
The usual geometry here is that the outside legs (opposite the vertical angles) are parallel, meaning that the angle indicators are the correct marks. It is possible, but unusual, for the red hash marks to be correct and the angle indicators to be mismarked. The red hash marks seem tentatively drawn, so seem like they're more likely to be the incorrect marks.
Answer:
Looks good to me!
Step-by-step explanation:
