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qwelly [4]
4 years ago
13

PLEASE QUICKLY HELP!!!!!

Mathematics
1 answer:
Sedaia [141]4 years ago
3 0
The answer is c.100/9
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Nick bought 6 tickets to an air show if he spent 156 dollars how much did the tickets cost
marysya [2.9K]

Answer:

$26 dollars

Step-by-step explanation: when you divide 156 divided by 6 you get 26

3 0
3 years ago
Read 2 more answers
3. A rectangular prism has dimensions of 1 , 2, and in. (a) What is the volume of the prism? Show your work and express your ans
Vedmedyk [2.9K]
Although you only put 2 of the 3 needed dimensions into the question, what you would do is multiply the 3 dimensions together and you would get your answer. To find the volume of a rectangular prism you multiply the width, the height, and the length. 
6 0
4 years ago
Write 1/3 x^2 - 4x + 17 in vertex form
Svetradugi [14.3K]

Answer:

f(x)=−4(x+ 41 ) 2 − 4 11

Explanation:

The given function is

f(x) = - 4 {x}^{2} - 2x - 3f(x)=−4x 2 −2x−3

To write the function is vertex form, we need to complete the square.

We first factor -4 to get:

f(x) = - 4 ({x}^{2} + \frac{1}{2} x) - 3f(x−4(x2 + 21 x)−3

Add and subtract the square of half the coefficient of x.

f(x) = - 4( {x}^{2} + \frac{1}{2} x + \frac{1}{16} ) - \frac{1}{4} - 3f(x)=−4(x 2 + 21 x+ 16 1 )− 41 −3

We factor the perfect square trinomial and simplify to get:

f(x) = - 4( {x + \frac{1}{4} )}^{2} - \frac{11}{4}f(x)=−4(x+ 41 ) 2 − 4 11

8 0
3 years ago
PLEASE HELP!! HURRY BUT I DON'T WANT GUESSES
Lorico [155]
The square on the hypotenuse is skew and impossible to visually validate. There's nothing to sum. It is a simple calculation to note that <span><span><span>32</span>+<span>42</span>=<span>52</span></span><span><span>32</span>+<span>42</span>=<span>52</span></span></span><span>, but its picture doesn't 'say' that the angle between the 3 and 4 sided square must be 90 degrees.


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7 0
3 years ago
Find the exact value of the trigonometric expression given that sin(u) = -(3/5),
GuDViN [60]

Recall that

\cot(u+v)=\dfrac{\cos(u+v)}{\sin(u+v)}=\dfrac{\cos u\cos v-\sin u\sin v}{\sin u\cos v+\cos u\sin v}=\dfrac{\cot u\cot v-1}{\cot v+\cot u}

Also, recall that for all \theta,

\cos^2\theta+\sin^2\theta=1

With \frac{3\pi}2, we can expect \cos u>0, and with 0, \sin v>0. So from the above identity it follows that

\cos u=\sqrt{1-\sin^2u}=\dfrac45\implies\cot u=\dfrac{\cos u}{\sin u}=-\dfrac43

and

\sin v=\sqrt{1-\cos^2v}=\dfrac8{17}\implies\cot v=\dfrac{\cos v}{\sin v}=\dfrac{15}8

and so

\cot(u+v)=\dfrac{-\frac43\frac{15}8-1}{\frac{15}8-\frac43}=\boxed{-\dfrac{84}{13}}

6 0
3 years ago
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