Answer:

And we can set equal this derivate to 0 in order to find the critical point and we got:


And we can calculate the second derivate and we got:

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094
Step-by-step explanation:
For this case we have the following function:

Where P represent the annual net income for the period 2007-2011 and 
And t represent the time in years since the start of 2005
In order to find the lowet income we need to use the derivate, given by:

And we can set equal this derivate to 0 in order to find the critical point and we got:


And we can calculate the second derivate and we got:

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094
-4x + 7 = 11
First, subtract 7 from both sides. / Your problem should look like:
Second, subtract 11 - 7. / Your problem should look like:
Third, divide both sides by -4. / Your problem should look like:
Fourth, change the fraction to a negative. / Your problem should look like:
Fifth, cancel 4 out. / Your problem should look like:

Answer:
x = -1
Answer:
Distance is the square root of (x2-x1)to the second power-(y2-y1)to the second power
Step-by-step explanation:
Just look up distance formula
Y = 3x - 1
The slope is 3, y goes up 3 for every increase in x
The intercept point of the Y axis is -1
Answer:
16/3
Step-by-step explanation: