If your original equation was $f(x) = 3(2)^x$ , then a reflection over the x-axis means you need all the y-values to switch sign. This means you need to multiply that function by -1.

$g(x) = -1\cdot 3(2)^x$ or $g(x) = -3(2)^x$

8 0

2 years ago

Solve the system of equations by substitution. What is the solution for x? (1 point)

Cerrena [4.2K]

       2x + y = 1
          2x - 2x + y = 1 - 2x
       y = 1 - 2x
       y = -2x + 1
       4x + 2y = -1
    4x + 2(-2x + 1) = -1
4x + 2(-2x) + 2(1) = -1
      4x - 4x + 2 = -1
         2 ≠ -1

The solution of the problem can't be a solution because they are both parallel lines, which means they have no solution.

8 0

3 years ago

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