Point a is at (-2,4) => (x1,y1)
Midpoint is (2.5, 3.5) => (a,b)
Point B is (x2, y2)
To find midpoint we use formula

a= 2.5, b= 3.5, x1= -2 and y1= 4
Plug in all the values and findout x2, y2

multiply 2 on both sides to remove fraction
(5 = -2+x2 , 7 = 4+ y2)
5 = -2+x2, so x2= 7
7 = 4+ y2, so y2= 3
The point B is ( 7, 3)
Answer:
1. In the multiplication of the imaginary parts, the student forgot to square of i. OR
2. The student has only multiplied the real parts and the imaginary parts.
Correct value
.
Step-by-step explanation:
The given expression is

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.
Student's mistake can be either 1 or second:
1. In the multiplication of the imaginary parts, the student forgot to square of i.
2. The student has only multiplied the real parts and the imaginary parts.

Which is not correct. The correct steps are shown below.
Using distributive property, we get



![[\because i^2=-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20i%5E2%3D-1%5D)


Therefore, the correct value of
is
.
1. tent
2. in
3. sert
4. ject
5. sert
6. de
Answer:well for the first one I am not sure but I think that since four is over the x there should be 4/x + 3 so tragically I don’t know the answer but I think it should be 12 the x should be 12 because 4x3=12 so yea 12
Step-by-step explanation:and for the other one I don’t know but ima try it should be two because 2x2=4 and so y=1-2x2-4 that’s what I think sorry. I got it wrong and do good on your test for me please