Answer is C: Hazard Communication
Hazard Communication Hazard (HCS 2012) provides a coherent and standardized approach to communicating the hazards of chemicals by way of Safety Data Sheets (SDSs) and labels on containers. However, Occupational Safety and Health Administration (OSHA) revised its HCS 2012. In it, they revised criteria for classification of chemical hazards, labeling provisions, hazard statements, and precautionary statements. In addition, modifications were made to health standards substances to ensure requirements for labels and SDSs are consistent with the HCS 2012. According to OSHA’S standards, SDSs should periodically be reviewed and updated.
Answer:
The output is 28
Explanation:
Required
Determine the output of the code segment
The first line initializes "answer" to 0
The next two lines iterate through lists [2,4] and [3,5
Each of these lists have two elements; So, the number of iterations is 2 * 2 i.e. 4.
In the first iteration
numA = 2, numB = 3, answer = 0
So:

In the second iteration
numA = 2, numB = 5, answer = 5
So:

In the third iteration
numA = 4, numB = 3, answer = 12
So:

In the fourth iteration
numA = 4, numB = 5, answer = 19
So:

Lastly, the value of "answer" is printed
<em>Hence, the output is 28</em>
Answer:
A virtual privte network is a particular type of network that uses circuits that run over the Internet but that appears to the user to be a private network.
Answer:
a) 255
b) 61602
c)
d)
Explanation:
You need to understand the decimal equivalent of hexadecimal numbers, <em>from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.</em>
For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:
a. F F
position 1 0
Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:

Finally, you'll add your results:
240+15=255
FF=255
b. F 0 A 2
position 3 2 1 0

F0A2=61602
c. F 1 0 0
position 3 2 1 0

0F100=61696
d. 1 0 0
position 2 1 0

100=256
I hope you find this information useful! Good luck!