A function that determines if a given year is a leap year:
#include<stdio.h>
int main()
{
//fill the code
int year, month;
scanf(“%d %d”,&month,&year);
if(!Leapyear(month, year))
{
if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12)
printf(“Number of days is 31”);
else if(month == 2)
{
printf(“Number of days is 28”);
}
else
printf(“Number of days is 30 “);
return 0;
}
}
int Leapyear(int month, int year)
{
if((month == 2) && (year%4 == 0) || ((year%100 == 0) &&(year%400 == 0)))
{
printf(“Number of days is 29”);
return 1;
}
else
return 0;
}
Class>settings>remove class
hope this helps :3
Answer:
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<u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>
It's to predict the behavior.