Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
The ratio of heights = ratio of the square roots of the areas because area is 2 dimensional and height is one dimensional.
so required ratio is sqrt 40pi : = sqrt40:sqrt80 = sqrt1: sqrt2 = sqrt (1/2) = 0.7071 to 4 significant figures
Answer:
3x^2 -7x +2
Step-by-step explanation:
(15x^2 -35x +10)÷5
15/5 x^2 -35/5 x +10/5
3x^2 -7x +2
Answer:
A variable is a letter, for example x, y or z, that represents an unspecified number.
6+x=12
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12.
If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.
Step-by-step explanation:
6z+4x=?
Solution: Replace x with 3 and z with 2 to evaluate the expression.
6z+4x=?
6⋅2+4⋅3=?
12+12=24
Hope this helps @(^_^)@
Answer:
the answer is 0.083
Step-by-step explanation:
