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n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Answer:
a.) 4/6
Step-by-step explanation:
3/5 = .6
<u><em>4/6 = .666666666667</em></u>
6/12= 0.5
3/8= .375
4/10= .4
Answer:
The correct answer is third option
x = 3
Step-by-step explanation:
It is given that,
4ˣ = 8⁽ˣ ⁻ ¹⁾
<u>To find the value of x</u>
4ˣ = (2²)ˣ
8⁽ˣ ⁻ ¹⁾ = (2³)⁽ˣ ⁻ ¹⁾
4ˣ = 8⁽ˣ ⁻ ¹⁾
(2²)ˣ = (2³)⁽ˣ ⁻ ¹⁾
2²ˣ = 2⁽³ˣ ⁻ ³⁾
2x = 3x - 3
3x - 2x = 3
x = 3
The correct answer is third option
x = 3
Answer:
x = -8
Step-by-step explanation:
Let's put this into numbers:
x =-6
The first thing you want to do is to multiply both sides by 4:
3x=-24
Next you need to divide by 3:
x=-8
The answer is -8