3 years ago

What is the length of ab

1 answer:

3 0

Apply the Pyth Thm twice:

diagonal of base is sqrt(4^2+6^2).

Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2

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sasho [114]

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Step-by-step explanation:

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polet [3.4K]

The equivalent expressions are:

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Solution:

Given expression is:

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Therefore,

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$3*4*6*2 = 144$

I guess that is the answer.

Hope this helps !

Photon

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