What is the length of ab

Mathematics

1 answer:

tia_tia [17]4 years ago

3 0

Apply the Pyth Thm twice:

diagonal of base is sqrt(4^2+6^2).

Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2

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How many square feet of outdoor carpet will we need for this hole?

kogti [31]

6+6+2 = 14

6 + 6 + 4 + 2 = 18

18+14 = 32

The answer is 32.

Hope this helps!

4 0

3 years ago

Read 2 more answers

Rewrite in simplest radical form 1/x^-3/6

VladimirAG [237]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad

\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\quad \\
% rational negative exponent
a^{-\frac{{ n}}{{ m}}} =
 \cfrac{1}{a^{\frac{{ n}}{{ m}}}} \implies \cfrac{1}{\sqrt[{ m}]{a^{ n}}}
\\ \quad \\ \quad \\

% radical denominator
\cfrac{1}{\sqrt[{ m}]{a^{ n}}}= \cfrac{1}{a^{\frac{{ n}}{{ m}}}}\implies a^{-\frac{{ n}}{{ m}}}\qquad thus\\
----------------------------\\

\\ \quad \\

$ $\bf 
\\ \quad \\

\cfrac{1}{x^{-\frac{3}{6}}}\implies \cfrac{1}{x^{-\frac{1}{2}}}\implies \cfrac{1}{\frac{1}{x\frac{1}{2}}}\implies \cfrac{1}{1}\cdot \cfrac{x^{\frac{1}{2}}}{1}
\\ \quad \\
x^{\frac{1}{2}}\implies \sqrt{x}$