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3 years ago

What is the length of ab

Mathematics

1 answer:

tia_tia [17]3 years ago

3 0

Apply the Pyth Thm twice:

diagonal of base is sqrt(4^2+6^2).

Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2

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Question 1 (1 point) How many terms are in the polynomial? 3x3 + 4x2 - 8x - 5 3 4 7

yKpoI14uk [10]

Answer:

Step-by-step explanation:

The polynomial 3x^3 +4x^2 -8x -5 has 4 terms. A term is a product or single variable or constant separated from other terms by a plus or minus sign.

The four terms are ...

3x^3
4x^2
-8x
-5

7 0

3 years ago

4x - 3 = 2x + 7 what would the answer be??

TiliK225 [7]

Answer:

x = 5

Step-by-step explanation:

Step 1: Subtract 2x from both sides.

4x−3−2x=2x+7−2x

Step 2: Add 3 to both sides.

2x−3+3=7+3

Step 3: Divide both sides by 2.

2x/2 = 10/2

x=5

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3 years ago

This is adding and subtracting binomials please help (13 points)

kkurt [141]

Answer:

-5x - 1

Step-by-step explanation:

Step 1: Write expression

(-6x + 2) + (x - 3)

Step 2: Combine like terms

-5x - 1

4 0

3 years ago

△OMT≅△HZE. If \text{m}\angle O = 51^{\circ}m∠O=51

professor190 [17]

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2 years ago

A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa

diamong [38]

Answer:

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}= \mu_D$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C,D$

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p=4$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

$p_v= 0.01$

Since the significance level is 0.05 we see that $pv$ so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0

3 years ago