All categories

3 years ago

Sheila has 5 times as many markers as Dave. together they have 18. how many markers does Sheila have???

Mathematics

2 answers:

wariber [46]3 years ago

7 0

5d+d=18
18 divided by 6 is 3 so Sheila has 15 markers and Dave has 3

Tems11 [23]3 years ago

5 0

Sheila has 5 times.
Dave has 1 time.
Together they have (5 + 1) = 6 times.

6 times = 18

Divide each side by 6 : 1 time = 3

Sheila has 5 times = (5 x 3) = 15 markers.

Dave has 1 time = 3 markers.

Total = (Sheila + Dave) = (15 + 3) = 18 markers.
Check, check , and double check.

You might be interested in

Kyoko is reading a book by her favorite author. She read the first 20 pages in One-half of an hour. Reading at the same pace, Ky

eduard

Answer:

It will take her 3 hours to read 120 pages.

Step-by-step explanation:

The number of pages read(y) after x hour can be modeled by a linear function in the following format:

$y = ax + b$

In which a is the number of pages read per hour and b is the initial number of pages read.

A straight line goes through (0, 0)

This means that when $x = 0, y = 0$

$y = ax + b$

$0 = a*0 + b$

$b = 0$

(0.5, 20)

When $x = 0.5, y = 20$

$y = ax$

$20 = 0.5a$

$a = \frac{20}{0.5}$

$a = 40$

The function in:

$y(x) = 40x$

According to the graph, which statement must be true?

It will take her 2 hours to read 60 pages.

$y(2) = 40*2 = 80$

Less than 2 hours for 60 pages, so this is false.

It will take her 3 hours to read 120 pages.

$y(3) = 40*3 = 120$

This statement is true.

It will take her 4 hours to read 180 pages.

$y(4) = 40*4 = 160$

More than 4 hours to read 180 pages. So false.

It will take her 5 hours to read 210 pages.

$y(5) = 40*5 = 200$

More than 5 hours to read 210 pages. So false.

6 0

4 years ago

Please answer this correctly I have to finish this today as soon as possible

Luba_88 [7]

Steps:

32yd. * 15yd. = 480 sq. yd

96 sq. yd. + 480 sq. yd = 576

Description:

We know that the prism is 13 yards long with a base of 12 yards and height of 8 yards. Meaning.

H = height

B = Base

P= Prism

The area of the prism each is 12yd * 8yd/2 = 48. So the two triangle combined area will be 96 yd. Meaning we get the number 32yd times it by 8 divide by 2 = the answer will equal as 48yd .The perimeter of both identical, isosceles triangles triangles are 10yd. + 10yd. + 12yd. = 32yd. and the length of those sides is 15yd. So the last step is to 32yd. * 15yd. = 480 sq. yd. Now you combine the two areas yields the total . 96 sq. yd. + 480 sq. yd = 576 sq. yd. total Answer will come as 576. Meanign the correct answer for this question is 576 yd.

Answer: 576 sq. yd. total

Please mark brainliest

Hope this helps.

5 0

3 years ago

A Halloween trick-or-treat group consists of 3 Trolls, 4 Nazguls, 4 Ents, and 5 Pokemon. A committee of 4 is to be picked to rep

balu736 [363]

Answer:

The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357

Step-by-step explanation:

No. of Trolls = 3

No. of Nazguls =4

No. of Ents = 4

No. of Pokemon = 5

Total Monsters = 16

We are given that A committee of 4 is to be picked to represent the group at the Monster Bash.

(a) Find the probability that the committee will consist of 1 from each type of monster.

So, the probability that the committee will consist of 1 from each type of monster:

= $\frac{^3C_1 \times ^4C_1 \times ^4C_1 \times ^5C_1}{^{16}C_4}$

= $\frac{\frac{3!}{1!(3-1)!} \times \frac{4!}{1!(4-1)!} \times \frac{4!}{1!(4-1)!}\times \frac{5!}{1!(5-1)!}}{\frac{16!}{4!(16-4)!}}$

= $\frac{\frac{3!}{1!(2)!} \times \frac{4!}{1!(3)!} \times \frac{4!}{1!(3)!}\times \frac{5!}{1!(4)!}}{\frac{16!}{4!(12)!}}$

= $0.1318$

b)Suppose that the Pokemon refuse to be on the same committee as a the Trolls.

So, the probability that this type of committee is formed

= $\frac{(^3C_3 \times ^8C_1)+(^3C_2 \times ^8C_2)+(^3C_1 \times ^8C_3)+(^3C_0 \times ^8C_4)+(^5C_4 \times ^8C_0)+(^5C_3 \times ^8C_1)+(^5C_2 \times ^8C_2)+(^5C_1 \times ^8C_3)}{^{16}C_4}$

= $\frac{(\frac{3!}{3!(3-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{3!}{2!(3-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{3!}{1!(3-1)!} \times\frac{8!}{3!(8-3)!})+(\frac{3!}{0!(3-0)!} \times \frac{8!}{4!(8-4)!})+(\frac{5!}{4!(5-4)!} \times \frac{8!}{0!(8-0)!})+(\frac{5!}{3!(5-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{5!}{2!(5-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{5!}{1!(5-1)!} \times \frac{8!}{3!(8-3)!})}{\frac{16!}{4!(16-4)!}}$

= $0.5357$

Hence The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357

4 0

3 years ago

How to find matrics M

makkiz [27]

$\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]$

$(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1$

$(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]$

3 0

3 years ago

The midpoint of VW is M(9, 8). One endpoint is W(8, 6). Find the coordinates of the other endpoint V.

Stells [14]

Answer:

you would find the slope from the midpoint to the endpoint and apply that to the other side, don't know exactly what the coordinates are.

Step-by-step explanation:

5 0

3 years ago