Answer:
See explanation below
Step-by-step explanation:
Find the value of x in each of the following
1) x-1+5√x-1+3=0
5√x-1 = -x -2
Square both sides
25(x-1) = (-x-2)^2
25(x-1) = x^2+4x + 4
25x-25 = x^2+4x + 4
x^2 +4x + 4 - 25x + 25 = 0
x^2 - 21x + 29 = 0
x = 21±√21²-4(29)/2
x = 21±√441-116/2
x = 21±√325/2
x = 21±18.03/2
x = 21+18.03/2 and 21-18.03/2
x = 19.515 and 1.485
4) x^4-64=0
x^4 = 64
![x = \sqrt[4]{64}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B4%5D%7B64%7D)
x = 2.83
Answer:
Slope - intercept form 
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given points are ( -9 ,-8 ) and (-6,6)
slope of given two points

The equation of the straight line passing through the points and having slope


3 y + 2 4 = 14 x + 126
3 y = 14 x + 126 - 24
3 y = 14 x + 102


Slope - intercept form y= mx +C
Slope - intercept form 
Answer:
45.7
Step-by-step explanation:
Hello there!
We can calculate the missing angle using trigonometry
here are the trigonometric ratios
sin = opposite over hypotenuse
cos = adjacent over hypotenuse
tan = opposite over adjacent
We are given x's opposite side length (8) and x's adjacent side length (7.8)
we are given the information to use the trigonometric ratio tangent
so now we create an equation (remember tan - opposite over tangent)

now we solve for x

we're left with

finally we want to get rid of the tan
To do so we take the inverse of tan (arctan^-1) and apply it to each side

so x = 45.7252243
finally we round to the nearest tenth and get that the answer is
45.7
Answer:
Line PQ
Step-by-step explanation:
diameter: straight line that passes through the centre of the circle (point O), and runs from on side of the circle to the other end (from point P to point Q)