To work out the determinant of a 3×3 matrix:
Multiply a by the determinant of the 2×2 matrix that is not in a's row or column
Likewise for b, and for c
sum them up, but remember the minus in front of the b
_____________________________________________________
Hope this helps, stay safe, have a good day :D
Answer:
5
Step-by-step explanation:
<h3>
Answer: <u>
11</u>
units to the <u>
right</u>
and <u>
3</u>
units <u>
down</u></h3>
====================================================
Explanation:
Plot the two points on the same xy grid (refer to the diagram below). Once this is done, the answer probably will become apparent. We should move point B 11 units to the right so that we move directly over top point B'. Count out the spaces to see why this is the case, or you can subtract the x coordinates and apply absolute value
|x1-x2| = |-5 - 6| = 11
Then we need to move 3 units down to finally arrive at point B'
---------------------------
A non-visual or non-graph approach could look like this:
B is at (-5,-2) while B' is at (6,-5)
Focus on the x coordinates for now. Like before, we subtract the x coordinates and apply absolute value to get |x1-x2| = |-5 - 6| = 11. This is the "11 units to the right" motion.
Do the same for the y coordinates to get |y1-y2| = |-2-(-5)| = 3. We move down because the y coordinate of B' is further away from 0 compared to the y coordinate of B.
In short, we apply the translation rule to describe the motion of right 11, down 3.
Complementary angles add up to 90 degrees whereas Supplementary angles add up to 180 degrees.
If this helps can I please have brainiest? Thanks
Diide both sides by -1
|j|=9
rememeber if |a|=b, then assume a=b and a=-b
so
j=9 and j=-9