Answer:
The correct answer is the third option: Lawyer - Probation Officer - Firefighter
Explanation:
First of all, the lawyer is the one who requires more years of schooling due to the fact that in order to be it the person must go to college after graduating from high school. Secondly, the probation officer is formed during years as well. And finally the firefighter is the one who does not need so many years of schooling because the person can go and have the training to be it right after he finished high school.
Answer:
The correct answer is option (B).
Explanation:
According to the scenario, the given data are as follows:
Purchased office supplies = $4,500
Supplies on balance account (in beginning) = $200
Supplies remaining (in end of month) = $180
So, To calculate supplies used in February we use following method:
Supplies Used = Supplies in Beginning + Purchased office supplies - Supplies in Ending
= $200 + $4,500 - $180
Supplies Used = $4,520
Hence, the amount of supplies USED during February was $4,520.
I am pretty sure it's to decide if the applicant is creditworthy. ( Makes most sense. Did research too.) :)
Phyllis' RATE (percentage) of return is 7 percent
<u>Explanation:</u>
Data provided in the question:
Purchase price for each share = $50
Dividend received = $1 per share
worth of shares at the end of year = $52.50
Thus, total return on the share = dividend received plus worth of sahres at the end of year minus purchase price
= $1 plus $52.50 minus $50 = $3.5
Therfore, rate of return = [ total return on the shares by purchase price ] into 100%
= [$3.5 by $50] inot 100 percent
= 7 percent
hence, the option with 7 percent will be the correct answer.
Answer:
Therefore after 16.26 unit of time, both accounts have same balance.
The both account have $8,834.43.
Explanation:
Formula for continuous compounding :
P(t)= value after t time
= Initial principal
r= rate of interest annually
t=length of time.
Given that, someone invested $5,000 at an interest 3.5% and another one invested $5,250 at an interest 3.2% .
Let after t year the both accounts have same balance.
For the first case,
P= $5,000, r=3.5%=0.035
For the second case,
P= $5,250, r=3.5%=0.032
According to the problem,
Taking ln both sides
Therefore after 16.26 unit of time, both accounts have same balance.
The account balance on that time is
=$8,834.43
The both account have $8,834.43.
