Answer:
1/64
Explanation:
<em>The probability of the offspring being homozygous dominant for the three alleles is 1/64.</em>
Since the three characters assort independently, the probability of the offspring being homozygous dominant for all the three traits is an independent event.
For independent events, the probability of all the events happening together is the multiplication of individual event's probability.
For a cross involving two heterozygotes, taking tall/dwarf for example:
Tt x Tt = TT, 2Tt, tt
The probability of obtaining a homozygous dominant genotype is 1/4.
Hence, the probability of the offspring being homozygous dominant for the three alleles will be:
1/4 x 1/4 x 1/4 = 1/64
Answer:
Because offspring with two parents will share half of each parent's DNA.
Explanation:
Sex cells contain half of the genetic information of an organism's regular cells. This is because a sexually-produced organism will be unique; it will share genetic information with both of its parents, rather than be identical to its bearer (like an asexual organism would be). When a sex cell meets another sex cell, their DNA will meet as well and change/adapt to suit the organism. If a sex cell had all the information needed to create an embyro, instead of half, which requires another cell's information to fill the DNA void.... well, it would just do it.
Answer:
they both have nucleus, cytoplasm, cell membrane and mitochondria
Explanation:
