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Aliun [14]
3 years ago
14

Rodney has 83 goldfish in his pond. In the winter, he wants to put the goldfish into one or more smaller fish tanks inside his h

ouse. He wants each fish tank to hold
the same number of goldfish. How many possible ways can the goldfish be placed into smaller fish tanks?
Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

0

Step-by-step explanation:

no number of tanks will hold the same amount of fish. 83 is a prime number, no numbers can be equally divided into it

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What is (8x-30)+6x+(2x+10) simplified?
VMariaS [17]

Answer:

16x-20

Step-by-step explanation:

(8x-30)+6x+(2x+10)

8x-30+6x+2x+10

8x+6x+2x-30+10

14x+2x-20

16x-20

3 0
3 years ago
A car goes around a turn too quickly, it can leave tracks that form an arc of a circle. By finding the radius of the circle, acc
ANTONII [103]

Check the picture below.

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3 0
2 years ago
SOMEONE PLEASE HELP ME FOR BRAINLY IF CORRECT
kifflom [539]

Answer:

A

Step-by-step explanation:

Its A which ever is the one that is full

5 0
3 years ago
Read 2 more answers
A car wash detailed 256 cars in 8 hours. At what rate did the car wash detail
Minchanka [31]
32 cars per hour. If you do 256 divided by 8 you get 32.

Hope this helped!
4 0
3 years ago
The answer to this question asap please
Mkey [24]

At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

<h3>How to state hypothesis conclusion?</h3>

We are given;

Sample size; n = 78

population standard deviation σ = 37

Sample Mean; x' = 280

Population mean; μ = 287

The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;

Null hypothesis; H₀: μ > 280

Alternative hypothesis; Hₐ: μ < 280

This is a one tail test with significance level of α  = 0.13

From online tables, the critical value at α  = 0.13 is z(c) = -1.13

b) Formula for the test statistic is;

z = (x-  μ)/(σ/√n)

z = ((280 - 287) *√78 )/37

z = -1.67

c) From online p-value from z-score calculator, we have;

P[ z > 280 ] =  0.048

d) The value for z = -1.67  is smaller than the critical value mentioned in problem statement z(c) = - 1.13  , the z(s) is in the rejection zone. Therefore we reject H₀

e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

Read more about Hypothesis Conclusion at; brainly.com/question/15980493

#SPJ1

5 0
2 years ago
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