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Aliun [14]
3 years ago
14

Rodney has 83 goldfish in his pond. In the winter, he wants to put the goldfish into one or more smaller fish tanks inside his h

ouse. He wants each fish tank to hold
the same number of goldfish. How many possible ways can the goldfish be placed into smaller fish tanks?
Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

0

Step-by-step explanation:

no number of tanks will hold the same amount of fish. 83 is a prime number, no numbers can be equally divided into it

You might be interested in
Find angle GEH, which is located inside inscribed hexagon ABCDEF.
Zinaida [17]

Answer:

60°

Step-by-step explanation:

Angle GHE = (360/6) ÷ 2 = 30

GEH = 180 - 90 - 30 = 60°

7 0
3 years ago
Could someone help me with this ASAP? thanks !
Maru [420]
<h3>Answer:</h3>

A. 6x^2+-5x+14x+-35

           6x^2+9x-35

B. 5x^4+-3x^3+10x^3+-6x^2

           5x^4+7x^3-6x^2

C. 25x^2+-20x+20x+-16

             25x^2-16

D. x^4+-4x^2+-7x^2+28

           x^4-11x^2+28

====================================

Step-by-step explanation:

A. (3x*2x)+(3x*-5)+(7*2x)+(7*-5)

        Multiply and simplify.

                6x^2+9x-35

B. (x^2*5x^2)+(x^2*-3x)+(2x*5x^2)+(2x*-3x)

         Multiply and simplify.

              5x^4+7x^3-6x^2

C. (5x*5x)+(5x*-4)+(4*5x)+(4*-4)

         Multiply and simplify.

                  25x^2-16

D. (x^2*x^2)+(x^2*-4)+(-7*x^2)+(-7*-4)

         Multiply and simplify.

                x^4-11x^2+28

I hope this helps!

But you should really do this yourself.

3 0
3 years ago
A study to compare the mean level of LDL cholesterol in male and female students who do not exercise regularly gave the data sho
Doss [256]
Female:                                     Male:
60                                              35
96                                             109
26                                              31
n₁=no. of entries=3                    n₂=no. of entries=3
s₁=sample standard                   s₂=sample standard 
      deviation=35.005                       deviation=43.924
x₁=sample mean=60.666           x₂=sample mean=58.333

Here s and x are calculated from calculator.
Now,
for significance level
1-α=90%
1-α=0.9
α=0.1
α/2=0.05

As population variances are unknown for both Male and female so the best suitable formula is

    (x₁ - x₂) ± tα/2,v₁ * \sqrt{ \frac{s_1^2 }{n_1} + \frac{s_2^2}{n_2} }
   ........1

where v(degree of fredom)=(s₁²/n₁+s₂²/n₂)² / ((s₁²/n₁)²/n₁-1)+(s₂²/n₂)²/n₂-1))
    by putting values 
           v=3.81026
From Statistics table,
      See the t table at α/2=0.05  and v=3.81026
use interpolation as v value is not in the table,
      3.81026-3/4-3 = x-3.182/2.776-3.182
                          x= 2.853
by putting values in eq. 1 we get
  
(60.666-58.333) ± (2.853)*\sqrt{ \frac{35.005^2 }{3} + \frac{43.924^2}{3} }      

  2.333 ± 92.516 is the correct answer.


8 0
3 years ago
Bob traveled 90 miles which was 83 1 3 % of his trip.<br> a<br> How long was the trip?
loris [4]

Total journey of bob was 108 miles .

<u>Step-by-step explanation:</u>

Here we have , Bob traveled 90 miles which was 83 1 3 % of his trip. We need to find How long was the trip .Let's find out:

According to question , Bob has traveled a distance of :

⇒ Distance = 90miles

Which is 83\frac{1}{3}\% of his journey . So , Let total  miles be x , So we have following equation framed according to question as :

⇒ \frac{83\frac{1}{3} x}{100} =90

⇒ \frac{83\frac{1}{3} x}{100}(100) =90(100)

⇒ \frac{83(3)+1}{3} x=90(100)

⇒ \frac{250}{3} x=9000

⇒ x=9000(\frac{3}{250} )

⇒ x=108miles

Therefore , Total journey of bob was 108 miles .

5 0
3 years ago
Help
lara31 [8.8K]

Answer : Let Natalie's age be x. Let Fred's age be y. Add​ Fred's age to 3 times​ Natalie's age, the result is 65. Answer : Natalie is 13 years old and Fred is 26 years old.

Step-by-step explanation:

so sorry is wong

7 0
3 years ago
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