What is the area of this?I need step by step

Mathematics

1 answer:

vitfil [10]3 years ago

7 0

Answer:

Driveway Area = 218 square feet
Garden Area = 230 square feet
Total Area = 448 square feet

See diagram below.

====================================================

Explanation:

Start at the lower left corner of the entire figure. Move 20 ft directly to the right until reach the end of the driveway at the bottom. Now move 10 ft up so you reach the other side of the driveway (the 26 ft side). In the process of moving 10 ft up, mark a new line segment. I've done so in red in the diagram below.

I've also drawn a green box. The red line and green box form a shape of a flag on a flagpole. The pole being 10 ft tall and the green box (flag) is a 6 by 3 rectangle. The 6 is from 26-20 = 6 and the 3 is from 10-7 = 3. Note how I'm subtracting the opposite side values to help figure out the dimensions of this green box.

The 10 ft by 20 ft portion of the driveway is 10*20 = 200 square feet. The green box adds on another 18 sq ft because 6*3 = 18. In all, we have 200+18 = 218 square feet for the driveway.

-------------------

If you want to know the area of the garden, then we first compute the overall area of everything shown. That's 32*14 = 448 square feet. Subtract off the driveway's area to get 448-218 = 230. Therefore, the garden's area is 230 square feet.

You might be interested in

Rob is saving to buy a new MP3 player. For every $15 he earns babysitting, he saves $10.On Saturday, Rob earned $45 babysitting.

Dmitrij [34]

Answer:

$30

Step-by-step explanation:

Okay, so we can solve this problem using fractions; $10 saved for every $15 made..

10/15=x/45

Using cross multiplication we can conclude 10*45=15x

450=15x

x=30

Hope this helps :)

7 0

2 years ago

I need help with #10

borishaifa [10]

Answer:

Step-by-step explanation:

this seems to be the line of best fit as it is centered in the data.

hope this helps!!

4 0

3 years ago

A student walk 60m on a bearing

Katena32 [7]

Answer:

d = 234.6 m

Step-by-step explanation:

You can consider a system of coordinates with its origin at the beginning of the walk of the student.

When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

$x_1=60cos28\°=52.97m\\\\y_1=60sin28\°=28.16m$

she is at the coordinates (52.97 , 28.16)m.

Next, when she walks 180m to the east, her coordinates are:

(52.97+180 , 28.16)m = (232.97 , 28.16)m

To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

$d=\sqrt{(x-x_o)^2+(y-y_o)^2}\\\\x=232.97\\\\x_o=0\\\\y=28.16\\\\y_o=0\\\\d=\sqrt{(232.97-0)^2+(28.16-0)^2}m=234.6m$