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jenyasd209 [6]
3 years ago
15

Hii help me pls this math test is so hard

Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0
The last 2 options I belive
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What is the perimeter of parallelogram ABDC?<br><br><br><br> 14 cm<br> 13 cm<br> 12 cm<br> 11 cm
Finger [1]

Answer:

13 cm

Step-by-step explanation:

Add up all of the sides and you should get 13.

3 + 3 + 3.5 + 3.5 = 13

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volume of a triangular pyramid is 232 cubic units. the area of the base is 29 square units. what is the height?!?!?
dedylja [7]
H= 3(v/LW)
LW= 29
3(232/29)
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15.6895 rounded to nearest tenth
il63 [147K]
Tenth is the first number after the decimal. If it's 5 or more than 5, then the number will increased by 1.

15.<u>6</u>895
Since the number after tenths is greater than 5, the number will be increased by 1

15.7 is the answer
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4 years ago
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Each child from a School can make 5 items of handicrafts in a day. If 1125 handicrafts items are to be displayed in an exhibitio
vladimir1956 [14]

Answer:

d)9

Step-by-step explanation:

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3 years ago
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The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
3 years ago
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