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Andru [333]
2 years ago
7

relay race is 1 4 mile long and is run by 4-member teams. If each team member runs the same distance, what fraction of a mile do

es each team member run? Explain how you found your answer.
Mathematics
1 answer:
sergejj [24]2 years ago
8 0

Answer:

7/20

Step-by-step explanation:

I did the work but Im not sure if this is right i just need points to ask my question. But what i did was i did 14 divided by 4=3.5, then moved the decimal in front of the 3 to make .35 then turned that into a fraction 7/20. AGAIN I DONT KNOW IF ITS RIGHT DONT BLAME ME IF ITS NOT

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Please answer it now in two minutes
makkiz [27]

Answer:

VX = 8.8 in

Step-by-step explanation:

By applying Sine rule in the right triangle WXV,

Sin(∠W) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

             = \frac{\text{VX}}{\text{WX}}

Sin(34)° = \frac{VX}{15}

VX = 15.Sin(34)°

     = 8.8379

     ≈ 8.8 in.

Therefore, measure of side VX is 8.8 in.

6 0
3 years ago
−4x−2y x−2y ​ =−2 =9 ​
fenix001 [56]
Dy\dx=-2+y/x+1 is the answer I think
7 0
2 years ago
WILL MARK BRAINLIEST!!!
Ludmilka [50]

Answer:

(C. one solution

Step-by-step explanation:

6 0
3 years ago
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Please Subtract the Following Fractions.
vovangra [49]

¡Hola!

Your answer to the question is 10/12.

Step-by-step explanation:

By using the y^2-y^1/x^2-x^1

12-2= 10

16-4= 12

So your answer is 10/12.

Hope this Helps!

4 0
2 years ago
GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out
Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

Area=length\times width

Area of garden and the walkway together is

Area=(14+2x)\times (10+2x)

396=140+28x+20x+4x^2

396=140+48x+4x^2

396=4(35+12x+x^2)

Divide both sides by 4.

99=35+12x+x^2

0=35-99+12x+x^2

0=-64+12x+x^2

Splitting the middle term, we get

x^2+16x-4x-64=0

x(x+16)-4(x+16)=0

(x+16)(x-4)=0

Using zero product property, we get

(x+16)=0\text{ and }(x-4)=0

x=-16\text{ and }x=4

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

6 0
2 years ago
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